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Theorem baibr 863
Description: Move conjunction outside of biconditional. (Contributed by NM, 11-Jul-1994.)
Hypothesis
Ref Expression
baib.1  |-  ( ph  <->  ( ps  /\  ch )
)
Assertion
Ref Expression
baibr  |-  ( ps 
->  ( ch  <->  ph ) )

Proof of Theorem baibr
StepHypRef Expression
1 baib.1 . . 3  |-  ( ph  <->  ( ps  /\  ch )
)
21baib 862 . 2  |-  ( ps 
->  ( ph  <->  ch )
)
32bicomd 139 1  |-  ( ps 
->  ( ch  <->  ph ) )
Colors of variables: wff set class
Syntax hints:    -> wi 4    /\ wa 102    <-> wb 103
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106
This theorem depends on definitions:  df-bi 115
This theorem is referenced by:  rbaibr  865  pm5.44  868  exmoeu2  1990  r19.9rmv  3340  dfopg  3576  brinxp  4434  elioo5  9032  prmind2  10646
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