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Theorem difeq1 3084
Description: Equality theorem for class difference. (Contributed by NM, 10-Feb-1997.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
Assertion
Ref Expression
difeq1  |-  ( A  =  B  ->  ( A  \  C )  =  ( B  \  C
) )

Proof of Theorem difeq1
Dummy variable  x is distinct from all other variables.
StepHypRef Expression
1 rabeq 2596 . 2  |-  ( A  =  B  ->  { x  e.  A  |  -.  x  e.  C }  =  { x  e.  B  |  -.  x  e.  C } )
2 dfdif2 2982 . 2  |-  ( A 
\  C )  =  { x  e.  A  |  -.  x  e.  C }
3 dfdif2 2982 . 2  |-  ( B 
\  C )  =  { x  e.  B  |  -.  x  e.  C }
41, 2, 33eqtr4g 2139 1  |-  ( A  =  B  ->  ( A  \  C )  =  ( B  \  C
) )
Colors of variables: wff set class
Syntax hints:   -. wn 3    -> wi 4    = wceq 1285    e. wcel 1434   {crab 2353    \ cdif 2971
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 663  ax-5 1377  ax-7 1378  ax-gen 1379  ax-ie1 1423  ax-ie2 1424  ax-8 1436  ax-10 1437  ax-11 1438  ax-i12 1439  ax-bndl 1440  ax-4 1441  ax-17 1460  ax-i9 1464  ax-ial 1468  ax-i5r 1469  ax-ext 2064
This theorem depends on definitions:  df-bi 115  df-tru 1288  df-nf 1391  df-sb 1687  df-clab 2069  df-cleq 2075  df-clel 2078  df-nfc 2209  df-rab 2358  df-dif 2976
This theorem is referenced by:  difeq12  3086  difeq1i  3087  difeq1d  3090  uneqdifeqim  3335  diffitest  6421
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