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Theorem elabf1 12915
Description: One implication of elabf 2801. (Contributed by BJ, 21-Nov-2019.)
Hypotheses
Ref Expression
elabf1.nf  |-  F/ x ps
elabf1.1  |-  ( x  =  A  ->  ( ph  ->  ps ) )
Assertion
Ref Expression
elabf1  |-  ( A  e.  { x  | 
ph }  ->  ps )
Distinct variable group:    x, A
Allowed substitution hints:    ph( x)    ps( x)

Proof of Theorem elabf1
StepHypRef Expression
1 nfcv 2258 . 2  |-  F/_ x A
2 elabf1.nf . 2  |-  F/ x ps
3 elabf1.1 . 2  |-  ( x  =  A  ->  ( ph  ->  ps ) )
41, 2, 3elabgf1 12913 1  |-  ( A  e.  { x  | 
ph }  ->  ps )
Colors of variables: wff set class
Syntax hints:    -> wi 4    = wceq 1316   F/wnf 1421    e. wcel 1465   {cab 2103
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 683  ax-5 1408  ax-7 1409  ax-gen 1410  ax-ie1 1454  ax-ie2 1455  ax-8 1467  ax-10 1468  ax-11 1469  ax-i12 1470  ax-bndl 1471  ax-4 1472  ax-17 1491  ax-i9 1495  ax-ial 1499  ax-i5r 1500  ax-ext 2099
This theorem depends on definitions:  df-bi 116  df-tru 1319  df-nf 1422  df-sb 1721  df-clab 2104  df-cleq 2110  df-clel 2113  df-nfc 2247  df-v 2662
This theorem is referenced by:  elab1  12917  bj-bdfindis  13072
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