Theorem nfan1 1497

Description: A closed form of nfan 1498. (Contributed by Mario Carneiro, 3-Oct-2016.)

Hypotheses

Ref	Expression
nfan1.1	|- F/ x ph
nfan1.2	|- ( ph -> F/ x ps )

Assertion

Ref	Expression
nfan1	|- F/ x ( ph /\ ps )

Proof of Theorem nfan1

Step	Hyp	Ref	Expression
1		nfan1.2	. . . . 5 |- ( ph -> F/ x ps )
2	1	nfrd 1454	. . . 4 |- ( ph -> ( ps -> A. x ps ) )
3	2	imdistani 434	. . 3 |- ( ( ph /\ ps ) -> ( ph /\ A. x ps ) )
4		nfan1.1	. . . . 5 |- F/ x ph
5	4	nfri 1453	. . . 4 |- ( ph -> A. x ph )
6	5	19.28h 1495	. . 3 |- ( A. x ( ph /\ ps ) <-> ( ph /\ A. x ps ) )
7	3, 6	sylibr 132	. 2 |- ( ( ph /\ ps ) -> A. x ( ph /\ ps ) )
8	7	nfi 1392	1 |- F/ x ( ph /\ ps )

Syntax hints:   -> wi 4   /\ wa 102   A.wal 1283   F/wnf 1390

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-5 1377  ax-gen 1379  ax-4 1441

This theorem depends on definitions:  df-bi 115  df-nf 1391

This theorem is referenced by:  nfan  1498  sbcralt  2891  sbcrext  2892  csbiebt  2943  riota5f  5523