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Mirrors > Home > ILE Home > Th. List > pwpw0ss | Unicode version |
Description: Compute the power set of the power set of the empty set. (See pw0 3637 for the power set of the empty set.) Theorem 90 of [Suppes] p. 48 (but with subset in place of equality). (Contributed by Jim Kingdon, 12-Aug-2018.) |
Ref | Expression |
---|---|
pwpw0ss |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | pwsnss 3700 | 1 |
Colors of variables: wff set class |
Syntax hints: wss 3041 c0 3333 cpw 3480 csn 3497 cpr 3498 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 ax-in1 588 ax-in2 589 ax-io 683 ax-5 1408 ax-7 1409 ax-gen 1410 ax-ie1 1454 ax-ie2 1455 ax-8 1467 ax-10 1468 ax-11 1469 ax-i12 1470 ax-bndl 1471 ax-4 1472 ax-17 1491 ax-i9 1495 ax-ial 1499 ax-i5r 1500 ax-ext 2099 |
This theorem depends on definitions: df-bi 116 df-tru 1319 df-nf 1422 df-sb 1721 df-clab 2104 df-cleq 2110 df-clel 2113 df-nfc 2247 df-v 2662 df-dif 3043 df-un 3045 df-in 3047 df-ss 3054 df-nul 3334 df-pw 3482 df-sn 3503 df-pr 3504 |
This theorem is referenced by: pp0ex 4083 exmidpw 6770 pw1dom2 13117 |
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