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Theorem anandi 532
Description: Distribution of conjunction over conjunction. (Contributed by NM, 14-Aug-1995.)
Assertion
Ref Expression
anandi ((𝜑 ∧ (𝜓𝜒)) ↔ ((𝜑𝜓) ∧ (𝜑𝜒)))

Proof of Theorem anandi
StepHypRef Expression
1 anidm 382 . . 3 ((𝜑𝜑) ↔ 𝜑)
21anbi1i 439 . 2 (((𝜑𝜑) ∧ (𝜓𝜒)) ↔ (𝜑 ∧ (𝜓𝜒)))
3 an4 528 . 2 (((𝜑𝜑) ∧ (𝜓𝜒)) ↔ ((𝜑𝜓) ∧ (𝜑𝜒)))
42, 3bitr3i 179 1 ((𝜑 ∧ (𝜓𝜒)) ↔ ((𝜑𝜓) ∧ (𝜑𝜒)))
Colors of variables: wff set class
Syntax hints:  wa 101  wb 102
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 103  ax-ia2 104  ax-ia3 105
This theorem depends on definitions:  df-bi 114
This theorem is referenced by:  anandi3  909  moanim  1990  difundi  3216  inrab  3236  uniin  3627  xpcom  4891  fin  5103  fndmin  5301  nnaord  6112  ltexprlemdisj  6761
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