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Theorem bibi2d 231
Description: Deduction adding a biconditional to the left in an equivalence. (Contributed by NM, 5-Aug-1993.) (Proof shortened by Wolf Lammen, 19-May-2013.)
Hypothesis
Ref Expression
imbid.1 (𝜑 → (𝜓𝜒))
Assertion
Ref Expression
bibi2d (𝜑 → ((𝜃𝜓) ↔ (𝜃𝜒)))

Proof of Theorem bibi2d
StepHypRef Expression
1 imbid.1 . . . . 5 (𝜑 → (𝜓𝜒))
21pm5.74i 179 . . . 4 ((𝜑𝜓) ↔ (𝜑𝜒))
32bibi2i 226 . . 3 (((𝜑𝜃) ↔ (𝜑𝜓)) ↔ ((𝜑𝜃) ↔ (𝜑𝜒)))
4 pm5.74 178 . . 3 ((𝜑 → (𝜃𝜓)) ↔ ((𝜑𝜃) ↔ (𝜑𝜓)))
5 pm5.74 178 . . 3 ((𝜑 → (𝜃𝜒)) ↔ ((𝜑𝜃) ↔ (𝜑𝜒)))
63, 4, 53bitr4i 211 . 2 ((𝜑 → (𝜃𝜓)) ↔ (𝜑 → (𝜃𝜒)))
76pm5.74ri 180 1 (𝜑 → ((𝜃𝜓) ↔ (𝜃𝜒)))
Colors of variables: wff set class
Syntax hints:  wi 4  wb 104
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107
This theorem depends on definitions:  df-bi 116
This theorem is referenced by:  bibi1d  232  bibi12d  234  biantr  936  bimsc1  947  eujust  1999  euf  2002  ceqex  2807  reu6i  2870  axsep2  4042  zfauscl  4043  copsexg  4161  euotd  4171  cnveq0  4990  iotaval  5094  iota5  5103  eufnfv  5641  isoeq1  5695  isoeq3  5697  isores2  5707  isores3  5709  isotr  5710  isoini2  5713  riota5f  5747  caovordg  5931  caovord  5935  dfoprab4f  6084  frecabcl  6289  nnaword  6400  xpf1o  6731  ltanqg  7201  ltmnqg  7202  ltasrg  7571  axpre-ltadd  7687  prmdvdsexp  11815  bdsep2  13073  bdzfauscl  13077  strcoll2  13170  sscoll2  13175
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