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Theorem ceqsrex2v 2698
Description: Elimination of a restricted existential quantifier, using implicit substitution. (Contributed by NM, 29-Oct-2005.)
Hypotheses
Ref Expression
ceqsrex2v.1 (𝑥 = 𝐴 → (𝜑𝜓))
ceqsrex2v.2 (𝑦 = 𝐵 → (𝜓𝜒))
Assertion
Ref Expression
ceqsrex2v ((𝐴𝐶𝐵𝐷) → (∃𝑥𝐶𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ 𝜒))
Distinct variable groups:   𝑥,𝑦,𝐴   𝑥,𝐵,𝑦   𝑥,𝐶   𝑥,𝐷,𝑦   𝜓,𝑥   𝜒,𝑦
Allowed substitution hints:   𝜑(𝑥,𝑦)   𝜓(𝑦)   𝜒(𝑥)   𝐶(𝑦)

Proof of Theorem ceqsrex2v
StepHypRef Expression
1 anass 387 . . . . . 6 (((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ (𝑥 = 𝐴 ∧ (𝑦 = 𝐵𝜑)))
21rexbii 2348 . . . . 5 (∃𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ ∃𝑦𝐷 (𝑥 = 𝐴 ∧ (𝑦 = 𝐵𝜑)))
3 r19.42v 2484 . . . . 5 (∃𝑦𝐷 (𝑥 = 𝐴 ∧ (𝑦 = 𝐵𝜑)) ↔ (𝑥 = 𝐴 ∧ ∃𝑦𝐷 (𝑦 = 𝐵𝜑)))
42, 3bitri 177 . . . 4 (∃𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ (𝑥 = 𝐴 ∧ ∃𝑦𝐷 (𝑦 = 𝐵𝜑)))
54rexbii 2348 . . 3 (∃𝑥𝐶𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ ∃𝑥𝐶 (𝑥 = 𝐴 ∧ ∃𝑦𝐷 (𝑦 = 𝐵𝜑)))
6 ceqsrex2v.1 . . . . . 6 (𝑥 = 𝐴 → (𝜑𝜓))
76anbi2d 445 . . . . 5 (𝑥 = 𝐴 → ((𝑦 = 𝐵𝜑) ↔ (𝑦 = 𝐵𝜓)))
87rexbidv 2344 . . . 4 (𝑥 = 𝐴 → (∃𝑦𝐷 (𝑦 = 𝐵𝜑) ↔ ∃𝑦𝐷 (𝑦 = 𝐵𝜓)))
98ceqsrexv 2696 . . 3 (𝐴𝐶 → (∃𝑥𝐶 (𝑥 = 𝐴 ∧ ∃𝑦𝐷 (𝑦 = 𝐵𝜑)) ↔ ∃𝑦𝐷 (𝑦 = 𝐵𝜓)))
105, 9syl5bb 185 . 2 (𝐴𝐶 → (∃𝑥𝐶𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ ∃𝑦𝐷 (𝑦 = 𝐵𝜓)))
11 ceqsrex2v.2 . . 3 (𝑦 = 𝐵 → (𝜓𝜒))
1211ceqsrexv 2696 . 2 (𝐵𝐷 → (∃𝑦𝐷 (𝑦 = 𝐵𝜓) ↔ 𝜒))
1310, 12sylan9bb 443 1 ((𝐴𝐶𝐵𝐷) → (∃𝑥𝐶𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ 𝜒))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 101  wb 102   = wceq 1259  wcel 1409  wrex 2324
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 103  ax-ia2 104  ax-ia3 105  ax-io 640  ax-5 1352  ax-7 1353  ax-gen 1354  ax-ie1 1398  ax-ie2 1399  ax-8 1411  ax-10 1412  ax-11 1413  ax-i12 1414  ax-bndl 1415  ax-4 1416  ax-17 1435  ax-i9 1439  ax-ial 1443  ax-i5r 1444  ax-ext 2038
This theorem depends on definitions:  df-bi 114  df-tru 1262  df-nf 1366  df-sb 1662  df-clab 2043  df-cleq 2049  df-clel 2052  df-nfc 2183  df-rex 2329  df-v 2576
This theorem is referenced by: (None)
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