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Mirrors > Home > ILE Home > Th. List > intnand | GIF version |
Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
Ref | Expression |
---|---|
intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
Ref | Expression |
---|---|
intnand | ⊢ (𝜑 → ¬ (𝜒 ∧ 𝜓)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
2 | simpr 109 | . 2 ⊢ ((𝜒 ∧ 𝜓) → 𝜓) | |
3 | 1, 2 | nsyl 617 | 1 ⊢ (𝜑 → ¬ (𝜒 ∧ 𝜓)) |
Colors of variables: wff set class |
Syntax hints: ¬ wn 3 → wi 4 ∧ wa 103 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia2 106 ax-in1 603 ax-in2 604 |
This theorem is referenced by: dcan 918 poxp 6122 cauappcvgprlemladdrl 7458 caucvgprlemladdrl 7479 xrrebnd 9595 fzpreddisj 9844 fzp1nel 9877 gcdsupex 11635 gcdsupcl 11636 gcdnncl 11645 gcd2n0cl 11647 qredeu 11767 cncongr2 11774 divnumden 11863 divdenle 11864 ivthinclemdisj 12776 |
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