Theorem necon3bbid 2348

Description: Deduction from equality to inequality. (Contributed by NM, 2-Jun-2007.)

Hypothesis

Ref	Expression
necon3bbid.1	⊢ (𝜑 → (𝜓 ↔ 𝐴 = 𝐵))

Assertion

Ref	Expression
necon3bbid	⊢ (𝜑 → (¬ 𝜓 ↔ 𝐴 ≠ 𝐵))

Proof of Theorem necon3bbid

Step	Hyp	Ref	Expression
1		necon3bbid.1	. . . 4 ⊢ (𝜑 → (𝜓 ↔ 𝐴 = 𝐵))
2	1	bicomd 140	. . 3 ⊢ (𝜑 → (𝐴 = 𝐵 ↔ 𝜓))
3	2	necon3abid 2347	. 2 ⊢ (𝜑 → (𝐴 ≠ 𝐵 ↔ ¬ 𝜓))
4	3	bicomd 140	1 ⊢ (𝜑 → (¬ 𝜓 ↔ 𝐴 ≠ 𝐵))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 104   = wceq 1331   ≠ wne 2308

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 603  ax-in2 604

This theorem depends on definitions:  df-bi 116  df-ne 2309

This theorem is referenced by:  necon3bid  2349  eldifsn  3650  prmrp  11823