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Theorem reseq1d 4636
Description: Equality deduction for restrictions. (Contributed by NM, 21-Oct-2014.)
Hypothesis
Ref Expression
reseqd.1 (𝜑𝐴 = 𝐵)
Assertion
Ref Expression
reseq1d (𝜑 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1d
StepHypRef Expression
1 reseqd.1 . 2 (𝜑𝐴 = 𝐵)
2 reseq1 4631 . 2 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
31, 2syl 14 1 (𝜑 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1257  cres 4372
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 103  ax-ia2 104  ax-ia3 105  ax-io 638  ax-5 1350  ax-7 1351  ax-gen 1352  ax-ie1 1396  ax-ie2 1397  ax-8 1409  ax-10 1410  ax-11 1411  ax-i12 1412  ax-bndl 1413  ax-4 1414  ax-17 1433  ax-i9 1437  ax-ial 1441  ax-i5r 1442  ax-ext 2036
This theorem depends on definitions:  df-bi 114  df-tru 1260  df-nf 1364  df-sb 1660  df-clab 2041  df-cleq 2047  df-clel 2050  df-nfc 2181  df-v 2574  df-in 2949  df-res 4382
This theorem is referenced by:  reseq12d  4638  fun2ssres  4968  funcnvres2  4999  funimaexg  5008  fresin  5093  offres  5787  tfrlemisucaccv  5967  tfrlemi1  5974  freceq1  6007  freceq2  6008  fseq1p1m1  9028
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