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Theorem resima2 4853
Description: Image under a restricted class. (Contributed by FL, 31-Aug-2009.)
Assertion
Ref Expression
resima2 (𝐵𝐶 → ((𝐴𝐶) “ 𝐵) = (𝐴𝐵))

Proof of Theorem resima2
StepHypRef Expression
1 df-ima 4552 . 2 ((𝐴𝐶) “ 𝐵) = ran ((𝐴𝐶) ↾ 𝐵)
2 resres 4831 . . . 4 ((𝐴𝐶) ↾ 𝐵) = (𝐴 ↾ (𝐶𝐵))
32rneqi 4767 . . 3 ran ((𝐴𝐶) ↾ 𝐵) = ran (𝐴 ↾ (𝐶𝐵))
4 df-ss 3084 . . . 4 (𝐵𝐶 ↔ (𝐵𝐶) = 𝐵)
5 incom 3268 . . . . . . . 8 (𝐶𝐵) = (𝐵𝐶)
65a1i 9 . . . . . . 7 ((𝐵𝐶) = 𝐵 → (𝐶𝐵) = (𝐵𝐶))
76reseq2d 4819 . . . . . 6 ((𝐵𝐶) = 𝐵 → (𝐴 ↾ (𝐶𝐵)) = (𝐴 ↾ (𝐵𝐶)))
87rneqd 4768 . . . . 5 ((𝐵𝐶) = 𝐵 → ran (𝐴 ↾ (𝐶𝐵)) = ran (𝐴 ↾ (𝐵𝐶)))
9 reseq2 4814 . . . . . . 7 ((𝐵𝐶) = 𝐵 → (𝐴 ↾ (𝐵𝐶)) = (𝐴𝐵))
109rneqd 4768 . . . . . 6 ((𝐵𝐶) = 𝐵 → ran (𝐴 ↾ (𝐵𝐶)) = ran (𝐴𝐵))
11 df-ima 4552 . . . . . 6 (𝐴𝐵) = ran (𝐴𝐵)
1210, 11syl6eqr 2190 . . . . 5 ((𝐵𝐶) = 𝐵 → ran (𝐴 ↾ (𝐵𝐶)) = (𝐴𝐵))
138, 12eqtrd 2172 . . . 4 ((𝐵𝐶) = 𝐵 → ran (𝐴 ↾ (𝐶𝐵)) = (𝐴𝐵))
144, 13sylbi 120 . . 3 (𝐵𝐶 → ran (𝐴 ↾ (𝐶𝐵)) = (𝐴𝐵))
153, 14syl5eq 2184 . 2 (𝐵𝐶 → ran ((𝐴𝐶) ↾ 𝐵) = (𝐴𝐵))
161, 15syl5eq 2184 1 (𝐵𝐶 → ((𝐴𝐶) “ 𝐵) = (𝐴𝐵))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1331  cin 3070  wss 3071  ran crn 4540  cres 4541  cima 4542
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 698  ax-5 1423  ax-7 1424  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-8 1482  ax-10 1483  ax-11 1484  ax-i12 1485  ax-bndl 1486  ax-4 1487  ax-14 1492  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-ext 2121  ax-sep 4046  ax-pow 4098  ax-pr 4131
This theorem depends on definitions:  df-bi 116  df-3an 964  df-tru 1334  df-nf 1437  df-sb 1736  df-clab 2126  df-cleq 2132  df-clel 2135  df-nfc 2270  df-ral 2421  df-rex 2422  df-v 2688  df-un 3075  df-in 3077  df-ss 3084  df-pw 3512  df-sn 3533  df-pr 3534  df-op 3536  df-br 3930  df-opab 3990  df-xp 4545  df-rel 4546  df-cnv 4547  df-dm 4549  df-rn 4550  df-res 4551  df-ima 4552
This theorem is referenced by:  cnptopresti  12407  cnptoprest  12408
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