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Theorem spimh 1700
Description: Specialization, using implicit substitition. Compare Lemma 14 of [Tarski] p. 70. The spim 1701 series of theorems requires that only one direction of the substitution hypothesis hold. (Contributed by NM, 5-Aug-1993.) (Revised by NM, 8-May-2008.) (New usage is discouraged.)
Hypotheses
Ref Expression
spimh.1 (𝜓 → ∀𝑥𝜓)
spimh.2 (𝑥 = 𝑦 → (𝜑𝜓))
Assertion
Ref Expression
spimh (∀𝑥𝜑𝜓)

Proof of Theorem spimh
StepHypRef Expression
1 spimh.2 . . . 4 (𝑥 = 𝑦 → (𝜑𝜓))
2 spimh.1 . . . 4 (𝜓 → ∀𝑥𝜓)
31, 2syl6com 35 . . 3 (𝜑 → (𝑥 = 𝑦 → ∀𝑥𝜓))
43alimi 1416 . 2 (∀𝑥𝜑 → ∀𝑥(𝑥 = 𝑦 → ∀𝑥𝜓))
5 ax9o 1661 . 2 (∀𝑥(𝑥 = 𝑦 → ∀𝑥𝜓) → 𝜓)
64, 5syl 14 1 (∀𝑥𝜑𝜓)
Colors of variables: wff set class
Syntax hints:  wi 4  wal 1314
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1408  ax-gen 1410  ax-ie1 1454  ax-ie2 1455  ax-4 1472  ax-i9 1495  ax-ial 1499
This theorem depends on definitions:  df-bi 116
This theorem is referenced by:  spim  1701
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