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Theorem sspssr 3040
Description: Subclass in terms of proper subclass. (Contributed by Jim Kingdon, 16-Jul-2018.)
Assertion
Ref Expression
sspssr ((𝐴𝐵𝐴 = 𝐵) → 𝐴𝐵)

Proof of Theorem sspssr
StepHypRef Expression
1 pssss 3036 . 2 (𝐴𝐵𝐴𝐵)
2 eqimss 2994 . 2 (𝐴 = 𝐵𝐴𝐵)
31, 2jaoi 636 1 ((𝐴𝐵𝐴 = 𝐵) → 𝐴𝐵)
Colors of variables: wff set class
Syntax hints:  wi 4  wo 629   = wceq 1243  wss 2914  wpss 2915
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-io 630  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-11 1397  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428  ax-ext 2022
This theorem depends on definitions:  df-bi 110  df-nf 1350  df-sb 1646  df-clab 2027  df-cleq 2033  df-clel 2036  df-in 2921  df-ss 2928  df-pss 2930
This theorem is referenced by: (None)
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