Theorem sylan9req 2193

Description: An equality transitivity deduction. (Contributed by NM, 23-Jun-2007.)

Hypotheses

Ref	Expression
sylan9req.1	⊢ (𝜑 → 𝐵 = 𝐴)
sylan9req.2	⊢ (𝜓 → 𝐵 = 𝐶)

Assertion

Ref	Expression
sylan9req	⊢ ((𝜑 ∧ 𝜓) → 𝐴 = 𝐶)

Proof of Theorem sylan9req

Step	Hyp	Ref	Expression
1		sylan9req.1	. . 3 ⊢ (𝜑 → 𝐵 = 𝐴)
2	1	eqcomd 2145	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
3		sylan9req.2	. 2 ⊢ (𝜓 → 𝐵 = 𝐶)
4	2, 3	sylan9eq 2192	1 ⊢ ((𝜑 ∧ 𝜓) → 𝐴 = 𝐶)

Syntax hints:   → wi 4   ∧ wa 103   = wceq 1331

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1423  ax-gen 1425  ax-4 1487  ax-17 1506  ax-ext 2121

This theorem depends on definitions:  df-bi 116  df-cleq 2132

This theorem is referenced by:  fndmu  5224  fodmrnu  5353  funcoeqres  5398  fvunsng  5614  prarloclem5  7308  addlocprlemeq  7341  zdiv  9139  resqrexlemnm  10790  dvdsmulc  11521  cncongrcoprm  11787