HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
Unicode version

Theorem ax11 1203
Description: Rederivation of axiom ax-11 1180 from the orginal version, ax-11o 1202.
Assertion
Ref Expression
ax11 |- (x = y -> (A.yph -> A.x(x = y -> ph)))

Proof of Theorem ax11
StepHypRef Expression
1 pm4.2i 171 . . . . 5 |- (A.x x = y -> (ph <-> ph))
21dral1 1137 . . . 4 |- (A.x x = y -> (A.xph <-> A.yph))
3 ax-1 4 . . . . 5 |- (ph -> (x = y -> ph))
4319.20i 968 . . . 4 |- (A.xph -> A.x(x = y -> ph))
52, 4syl6bir 215 . . 3 |- (A.x x = y -> (A.yph -> A.x(x = y -> ph)))
65a1d 12 . 2 |- (A.x x = y -> (x = y -> (A.yph -> A.x(x = y -> ph))))
7 ax-11o 1202 . . 3 |- (-. A.x x = y -> (x = y -> (ph -> A.x(x = y -> ph))))
8 ax-4 951 . . 3 |- (A.yph -> ph)
97, 8syl7 23 . 2 |- (-. A.x x = y -> (x = y -> (A.yph -> A.x(x = y -> ph))))
106, 9pm2.61i 126 1 |- (x = y -> (A.yph -> A.x(x = y -> ph)))
Colors of variables: wff set class
Syntax hints:  -. wn 2   -> wi 3  A.wal 950   = wceq 1099
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-4 951  ax-5 952  ax-6 953  ax-7 954  ax-gen 955  ax-8 1101  ax-9 1102  ax-10 1103  ax-12 1104  ax-11o 1202
This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 957
Copyright terms: Public domain