HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
Unicode version

Theorem ax11i 1138
Description: Inference that has ax-11 967 (without A.y) as its conclusion and doesn't require ax-10 966, ax-11 967, or ax-12 968 for its proof. The hypotheses may be eliminable without one or more of these axioms in special cases. Proof similar to Lemma 16 of [Tarski] p. 70.
Hypotheses
Ref Expression
ax11i.1 |- (x = y -> (ph <-> ps))
ax11i.2 |- (ps -> A.xps)
Assertion
Ref Expression
ax11i |- (x = y -> (ph -> A.x(x = y -> ph)))

Proof of Theorem ax11i
StepHypRef Expression
1 ax11i.1 . 2 |- (x = y -> (ph <-> ps))
2 ax11i.2 . . 3 |- (ps -> A.xps)
31biimprcd 156 . . 3 |- (ps -> (x = y -> ph))
42, 319.21ai 998 . 2 |- (ps -> A.x(x = y -> ph))
51, 4syl6bi 214 1 |- (x = y -> (ph -> A.x(x = y -> ph)))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 146  A.wal 954   = wceq 956
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 963  ax-4 973  ax-5o 975
This theorem depends on definitions:  df-bi 147
Copyright terms: Public domain