Theorem disj2 2320

Description: Two ways of saying that two classes are disjoint.

Assertion

Ref	Expression
disj2	|- ((A i^i B) = (/) <-> A (_ (V \ B))

Proof of Theorem disj2

Step	Hyp	Ref	Expression
1		ssv 2084	. 2 |- A (_ V
2		reldisj 2317	. 2 |- (A (_ V -> ((A i^i B) = (/) <-> A (_ (V \ B)))
3	1, 2	ax-mp 7	1 |- ((A i^i B) = (/) <-> A (_ (V \ B))

Syntax hints:   <-> wb 146   = wceq 958  Vcvv 1814   \ cdif 2047   i^i cin 2049   (_ wss 2050  (/)c0 2283

This theorem is referenced by:  ssindif0 2326

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-10 968  ax-12 970  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220  ax-ext 1462

This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 983  df-sb 1174  df-clab 1467  df-cleq 1472  df-clel 1475  df-ral 1652  df-v 1815  df-dif 2052  df-in 2054  df-ss 2056  df-nul 2284

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