Theorem equs5 1221

Description: Lemma used in proofs of substitution properties.

Assertion

Ref	Expression
equs5	|- (-. A.x x = y -> (E.x(x = y /\ ph) -> A.x(x = y -> ph)))

Proof of Theorem equs5

Step	Hyp	Ref	Expression
1		hbnae 1146	. 2 |- (-. A.x x = y -> A.x -. A.x x = y)
2		hba1 1002	. 2 |- (A.x(x = y -> ph) -> A.xA.x(x = y -> ph))
3		ax-11o 1218	. . 3 |- (-. A.x x = y -> (x = y -> (ph -> A.x(x = y -> ph))))
4	3	imp3a 361	. 2 |- (-. A.x x = y -> ((x = y /\ ph) -> A.x(x = y -> ph)))
5	1, 2, 4	19.23ad 1065	1 |- (-. A.x x = y -> (E.x(x = y /\ ph) -> A.x(x = y -> ph)))

Syntax hints:  -. wn 2   -> wi 3   /\ wa 223  A.wal 953   = wceq 955  E.wex 979

This theorem is referenced by:  sb3 1222  sb4 1223

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 961  ax-gen 962  ax-10 965  ax-12 967  ax-4 972  ax-5o 974  ax-6o 977  ax-10o 1139  ax-11o 1218

This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 980

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