Theorem equtr 1168

Description: A transitive law for equality.

Assertion

Ref	Expression
equtr	|- (x = y -> (y = z -> x = z))

Proof of Theorem equtr

Step	Hyp	Ref	Expression
1		ax-8 1000	. 2 |- (y = x -> (y = z -> x = z))
2	1	equcoms 1167	1 |- (x = y -> (y = z -> x = z))

Syntax hints:   -> wi 3   = wceq 992

This theorem is referenced by:  equtrr 1169  equtr2 1170  equequ1 1171  equvin 1313  a12lem1 1415  axsep 2776  dscmet 8129

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 999  ax-8 1000  ax-12 1004  ax-4 1009  ax-5o 1011  ax-6o 1014  ax-9o 1159

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