Theorem hbia1 1014

Description: Lemma 23 of [Monk2] p. 114.

Assertion

Ref	Expression
hbia1	|- ((A.xph -> A.xps) -> A.x(A.xph -> A.xps))

Proof of Theorem hbia1

Step	Hyp	Ref	Expression
1		hba1 1003	. 2 |- (A.xph -> A.xA.xph)
2		hba1 1003	. 2 |- (A.xps -> A.xA.xps)
3	1, 2	hbim 1007	1 |- ((A.xph -> A.xps) -> A.x(A.xph -> A.xps))

Syntax hints:   -> wi 3  A.wal 954

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 963  ax-4 973  ax-5o 975  ax-6o 978

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