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Theorem merlem3 924
Description: Step 7 of Meredith's proof of Lukasiewicz axioms from his sole axiom.
Assertion
Ref Expression
merlem3 |- (((ps -> ch) -> ph) -> (ch -> ph))

Proof of Theorem merlem3
StepHypRef Expression
1 merlem2 923 . . . 4 |- (((-. ch -> -. ch) -> (-. ch -> -. ch)) -> ((ph -> ph) -> (-. ch -> -. ch)))
2 merlem2 923 . . . 4 |- ((((-. ch -> -. ch) -> (-. ch -> -. ch)) -> ((ph -> ph) -> (-. ch -> -. ch))) -> ((((ch -> ph) -> (-. ps -> -. ps)) -> ps) -> ((ph -> ph) -> (-. ch -> -. ch))))
31, 2ax-mp 7 . . 3 |- ((((ch -> ph) -> (-. ps -> -. ps)) -> ps) -> ((ph -> ph) -> (-. ch -> -. ch)))
4 meredith 921 . . 3 |- (((((ch -> ph) -> (-. ps -> -. ps)) -> ps) -> ((ph -> ph) -> (-. ch -> -. ch))) -> ((((ph -> ph) -> (-. ch -> -. ch)) -> ch) -> (ps -> ch)))
53, 4ax-mp 7 . 2 |- ((((ph -> ph) -> (-. ch -> -. ch)) -> ch) -> (ps -> ch))
6 meredith 921 . 2 |- (((((ph -> ph) -> (-. ch -> -. ch)) -> ch) -> (ps -> ch)) -> (((ps -> ch) -> ph) -> (ch -> ph)))
75, 6ax-mp 7 1 |- (((ps -> ch) -> ph) -> (ch -> ph))
Colors of variables: wff set class
Syntax hints:  -. wn 2   -> wi 3
This theorem is referenced by:  merlem4 925  merlem6 927
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7
Copyright terms: Public domain