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Statement List for Metamath Proof Explorer - 4501-4600 - Page 46 of 107
TypeLabelDescription
Statement
 
Theoremssenen 4501 Equinumerosity of equinumerous subsets of a set.
|- A e. V   &   |- B e. V   =>   |- (A ~~ B -> {x | (x (_ A /\ x ~~ C)} ~~ {x | (x (_ B /\ x ~~ C)})
 
Theoremlimenpsi 4502 A limit ordinal is equinumerous to a proper subset of itself.
|- Lim A   =>   |- (A e. B -> A ~~ (A \ {(/)}))
 
Theoremlimensuci 4503 A limit ordinal is equinumerous to its successor.
|- Lim A   =>   |- (A e. B -> A ~~ suc A)
 
Theoremlimensuc 4504 A limit ordinal is equinumerous to its successor.
|- ((A e. B /\ Lim A) -> A ~~ suc A)
 
Pigeonhole Principle
 
Theoremphplem1 4505 Lemma for Pigeonhole Principle. If we join a natural number to itself minus an element, we end up with its successor minus the same element.
 
Theoremphplem2 4506 Lemma for Pigeonhole Principle. A natural number is equinumerous to its successor minus one of its elements.
 
Theoremphplem3 4507 Lemma for Pigeonhole Principle. A natural number is equinumerous to its successor minus any element of the successor.
 
Theoremphplem4 4508 Lemma for Pigeonhole Principle. Equinumerosity of successors implies equinumerosity of the original natural numbers.
 
Theoremnneneq 4509 Two equinumerous natural numbers are equal. Proposition 10.20 of [TakeutiZaring] p. 90 and its converse. Also compare Corollary 6E of [Enderton] p. 136.
|- ((A e. om /\ B e. om) -> (A ~~ B <-> A = B))
 
Theoremphp 4510 Pigeonhole Principle. A natural number is not equinumerous to a proper subset of itself. Theorem (Pigeonhole Principle) of [Enderton] p. 134. The theorem is so-called because you can't put n + 1 pigeons into n holes (if each hole holds only one pigeon). The proof consists of lemmas phplem1 4505 through phplem4 4508, nneneq 4509, and this final piece of the proof.
|- ((A e. om /\ B (. A) -> -. A ~~ B)
 
Theoremphp2 4511 Corollary of Pigeonhole Principle.
|- ((A e. om /\ B (. A) -> B ~< A)
 
Theoremphp3 4512 Corollary of Pigeonhole Principle. If A is finite and B is a proper subset of A, the B is strictly less numerous than A. Stronger version of Corollary 6C of [Enderton] p. 135. (The expression E.x e. omA ~~ x is the definition of "finite," and "infinite" is defined as "not finite.")
|- ((E.x e. om A ~~ x /\ B (. A) -> B ~< A)
 
Theoremphp4 4513 Corollary of the Pigeonhole Principle php 4510: a natural number is strictly dominated by its successor.
|- (A e. om -> A ~< suc A)
 
Theoremphp5 4514 Corollary of the Pigeonhole Principle php 4510: a natural number is not equinumerous to its successor. Corollary 10.21(1) of [TakeutiZaring] p. 90.
|- (A e. om -> -. A ~~ suc A)
 
Finite sets
 
Theoremonomeneq 4515 An ordinal number equinumerous to a natural number is equal to it. Proposition 10.22 of [TakeutiZaring] p. 90 and its converse.
|- ((A e. On /\ B e. om) -> (A ~~ B <-> A = B))
 
Theoremonfin 4516 An ordinal number is finite iff it is a natural number. Proposition 10.32 of [TakeutiZaring] p. 92.
|- (A e. On -> (E.x e. om A ~~ x <-> A e. om))
 
Theoremnndomo 4517 Cardinal ordering agrees with natural number ordering. Example 3 of [Enderton] p. 146.
|- ((A e. om /\ B e. om) -> (A ~<_ B <-> A (_ B))
 
Theoremnnsdomo 4518 Cardinal ordering agrees with natural number ordering.
|- ((A e. om /\ B e. om) -> (A ~< B <-> A (. B))
 
Theoremomsucdom 4519 Strict dominance of natural numbers is the same as dominance over the successor of the smaller.
|- ((A e. om /\ B e. om) -> (A ~< B <-> suc A ~<_ B))
 
Theoremsucdomi 4520 Dominance of a set over a successor of a natural number implies strict dominance over the number. For the converse, see sucdom 4833.
|- ((A e. om /\ B e. C) -> (suc A ~<_ B -> A ~< B))
 
Theorem0sdom1dom 4521 Strict dominance over zero is the same as dominance over one.
|- A e. V   =>   |- ((/) ~< A <-> 1o ~<_ A)
 
Theorem1sdom2 4522 Ordinal 1 is strictly dominated by ordinal 2.
|- 1o ~< 2o
 
Theoremfinsucdom 4523 Strict dominance of a finite set over a natural number is the same as dominance over its successor.
|- ((A e. om /\ E.x e. om B ~~ x) -> (A ~< B <-> suc A ~<_ B))
 
Theorempssinf 4524 A set equinumerous to a proper subset of itself is infinite. Corollary 6D(a) of [Enderton] p. 136.
|- ((A (. B /\ A ~~ B) -> -. E.x e. om B ~~ x)
 
Theoremominf 4525 The set of natural numbers is infinite. Corollary 6D(b) of [Enderton] p. 136.
|- -. E.x e. om om ~~ x
 
Theoremomsdomnn 4526 Omega strictly dominates a natural number. Example 3 of [Enderton] p. 146. Here we use A ~<_ om /\ -. om ~~ A instead of A ~< om because, due to a peculiarity ultimately caused our ordered pair definition, we would need the Axiom of infinity (which we have avoided up to now) in order to prove the latter.
|- (A e. om -> (A ~<_ om /\ -. om ~~ A))
 
Theoremisfinite1 4527 Omega strictly dominates a finite set. See comment in omsdomnn 4526.
|- (E.x e. om A ~~ x -> (A ~<_ om /\ -. om ~~ A))
 
Theoreminfsdomnn 4528 An infinite set strictly dominates a natural number.
|- A e. V   =>   |- ((om ~<_ A /\ B e. om) -> B ~< A)
 
Theoreminfn0 4529 An infinite set is not empty.
|- A e. V   =>   |- (om ~<_ A -> A =/= (/))
 
Theorempssnn 4530 A proper subset of a natural number is equinumerous to some smaller number. Lemma 6F of [Enderton] p. 137.
|- ((A e. om /\ B (. A) -> E.x e. A B ~~ x)
 
Theoremssnn 4531 A subset of a natural number is finite.
|- ((A e. om /\ B (_ A) -> E.x e. om B ~~ x)
 
Theoremssfi 4532 A subset of a finite set is finite. Corollary 6G of [Enderton] p. 138.
|- ((E.x e. om A ~~ x /\ B (_ A) -> E.x e. om B ~~ x)
 
Theoremdomfi 4533 A set dominated by a finite set is finite.
|- ((E.x e. om A ~~ x /\ B ~<_ A) -> E.x e. om B ~~ x)
 
Theoremunblem1 4534 Lemma for unbnn 4538. After removing the successor of an element from an unbounded set of natural numbers, the intersection of the result belongs to the original unbounded set.
 
Theoremunblem2 4535 Lemma for unbnn 4538. The value of the function F belongs to the unbounded set of natural numbers A.
 
Theoremunblem3 4536 Lemma for unbnn 4538. The value of the function F is less than its value at a successor.
 
Theoremunblem4 4537 Lemma for unbnn 4538. The function F maps the set of natural numbers one-to-one to the set of unbounded natural numbers A.
 
Theoremunbnn 4538 Any unbounded subset of natural numbers is equinumerous to the set of all natural numbers. Part of the proof of Theorem 42 of [Suppes] p. 151. See unbnnt 4630 for a stronger version without the hypothesis.
|- A e. V   =>   |- ((A (_ om /\ A.x e. om E.y e. A x e. y) -> A ~~ om)
 
Theoremunbnn2 4539 Version of unbnn 4538 that does not require a strict upper bound.
|- A e. V   =>   |- ((A (_ om /\ A.x e. om E.y e. A x (_ y) -> A ~~ om)
 
Theoremisfinite2 4540 Any set strictly dominated by the class of natural numbers is finite. Sufficiency part of Theorem 42 of [Suppes] p. 151. This theorem does not require the Axiom of Infinity.
|- (A ~< om -> E.x e. om A ~~ x)
 
Theoremunfilem1 4541 Lemma for proving that the union of two finite sets is finite.
 
Theoremunfilem2 4542 Lemma for proving that the union of two finite sets is finite.
 
Theoremunfilem3 4543 Lemma for proving that the union of two finite sets is finite.
 
Theoremfin2inf 4544 This theorem, which was proved without the Axiom of Infinity, is an artifact of our definition of strict dominance, which is meaningful only when its arguments exist. In particular, the antecedent cannot be satisfied unless om exists.
|- (A ~< om -> om e. V)
 
Theoremunfi 4545 The union of two finite sets is finite. Part of Corollary 6K of [Enderton] p. 144.
|- ((E.x e. om A ~~ x /\ E.x e. om B ~~ x) -> E.x e. om (A u. B) ~~ x)
 
Theoremunfi2 4546 The union of two finite sets is finite. Part of Corollary 6K of [Enderton] p. 144. This version of unfi 4545 is useful only if we assume the Axiom of Infinity (see comments in fin2inf 4544).
|- ((A ~< om /\ B ~< om) -> (A u. B) ~< om)
 
Theoreminfcntss 4547 Every infinite set has a denumerable subset. Similar to Exercise 8 of [TakeutiZaring] p. 91. (However, we need neither AC nor the Axiom of Infinity because of the way we express "infinite" in the antecedent.)
|- A e. V   =>   |- (om ~<_ A -> E.x(x (_ A /\ x ~~ om))
 
Theoremprfi 4548 An unordered pair is finite.
|- E.x e. om {A, B} ~~ x
 
Theoremunifi 4549 The finite union of finite sets is finite. Exercise 13 of [Enderton] p. 144.
|- ((E.n e. om A ~~ n /\ A.x e. A E.n e. om x ~~ n) -> E.n e. om U.A ~~ n)
 
Theoremunifi2 4550 The finite union of finite sets is finite. Exercise 13 of [Enderton] p. 144. This version of unifi 4549 is useful only if we assume the Axiom of Infinity (see comments in fin2inf 4544).
|- ((A ~< om /\ A.x e. A x ~< om) -> U.A ~< om)
 
Theoremfiint 4551 Equivalent ways of stating the finite intersection property. We show two ways of saying, "the intersection of elements in every finite non-empty subcollection of A is in A." This theorem is applicable to a topology, which (among other axioms) is closed under finite intersections. Some texts use the left-hand version of this axiom and others the right-hand version, but as our proof here shows, their "intuitively obvious" equivalence can be non-trivial to establish formally.
|- (A.x e. A A.y e. A (x i^i y) e. A <-> A.x((x (_ A /\ x =/= (/) /\ E.y e. om x ~~ y) -> |^|x e. A))
 
Theoremabfii1 4552 Two ways to express the collection of finite intersections of a set A.
|- |^|{x | (A (_ x /\ A.y e. x A.z e. x (y i^i z) e. x)} = |^|{x | (A (_ x /\ A.y((y (_ x /\ y =/= (/) /\ E.z e. om y ~~ z) -> |^|y e. x))}
 
Theoremabfii2 4553 Two ways to express the collection of finite intersections of a set A.
|- A e. V   =>   |- {x | E.y(y (_ A /\ E.z e. om y ~~ z /\ x = |^|y)} = |^|{x | A.y((y (_ A /\ y =/= (/) /\ E.z e. om y ~~ z) -> |^|y e. x)}
 
Theoremabfii3 4554 Two ways to express the collection of finite intersections of a set A.
|- A e. V   =>   |- |^|{x | (A (_ x /\ A.y((y (_ A /\ y =/= (/) /\ E.z e. om y ~~ z) -> |^|y e. x))} = |^|{x | A.y((y (_ A /\ y =/= (/) /\ E.z e. om y ~~ z) -> |^|y e. x)}
 
Theoremabfii4 4555 Two ways to express the collection of finite intersections of a set A. Even though the expressions differ by only one symbol, the proof is not simple.
|- A e. V   =>   |- |^|{x | (A (_ x /\ A.y((y (_ x /\ y =/= (/) /\ E.z e. om y ~~ z) -> |^|y e. x))} = |^|{x | (A (_ x /\ A.y((y (_ A /\ y =/= (/) /\ E.z e. om y ~~ z) -> |^|y e. x))}
 
Theoremabfii5 4556 Two ways to express the collection of finite intersections of a set A.
|- A e. V   =>   |- |^|{x | (A (_ x /\ A.y e. x A.z e. x (y i^i z) e. x)} = {x | E.y(y (_ A /\ E.z e. om y ~~ z /\ x = |^|y)}
 
Theoremfodomfi 4557 An onto function implies dominance of domain over range, for finite sets. Unlike fodom 4789 for arbitrary sets, this theorem does not require the Axiom of Choice for its proof.
|- ((E.n e. om A ~~ n /\ F:A-onto->B) -> B ~<_ A)
 
Theoremfodomfib 4558 Equivalence of an onto mapping and dominance for a non-empty finite set. Unlike fodomb 4791 for arbitrary sets, this theorem does not require the Axiom of Choice for its proof.
|- (E.n e. om A ~~ n -> ((A =/= (/) /\ E.f f:A-onto->B) <-> ((/) ~< B /\ B ~<_ A)))
 
Theoremfofi 4559 If a function has a finite domain, its range is finite. Theorem 37 of [Suppes] p. 104.
|- ((E.n e. om A ~~ n /\ F:A-onto->B) -> E.n e. om B ~~ n)
 
Theoremiunfi 4560 The finite union of finite sets is finite. Exercise 13 of [Enderton] p. 144. This is the indexed union version of unifi 4549. Note that B depends on x, i.e. can be thought of as B(x).
|- ((E.n e. om A ~~ n /\ A.x e. A E.n e. om B ~~ n) -> E.n e. om U_x e. A B ~~ n)
 
Theorempwfilem 4561 Lemma for pwfi 4562.
 
Theorempwfi 4562 The power set of a finite set is finite and vice-versa. Theorem 38 of [Suppes] p. 104 and its converse, Theorem 40 of [Suppes] p. 105.
|- (E.n e. om A ~~ n <-> E.n e. om P~A ~~ n)
 
Theorempm54.43 4563 Theorem *54.43 of [WhiteheadRussell] p. 360. "From this proposition it will follow, when arithmetical addition has been defined, that 1+1=2." See http://en.wikipedia.org/wiki/Principia_Mathematica#Quotations. This theorem states that two sets of cardinality 1 are disjoint iff their union has cardinality 2.

Whitehead and Russell define 1 as the collection of all sets with cardinality 1 (i.e. all singletons; see card1 4824), so that their A e. 1 means, in our notation, A e. {x | (card` x) = 1o} i.e. (card` A) = 1o (by elab 1893) i.e. A ~~ 1o (by carden 4822 and cardnn 4815). We do not have several of their earlier lemmas available (which would otherwise be unused by our different approach to arithmetic), so our proof is longer. (It is also longer because we must show every detail.)

Theorem pm110.643 4914 shows the derivation of 1+1=2 for cardinal numbers from this theorem.

|- ((A ~~ 1o /\ B ~~ 1o) -> ((A i^i B) = (/) <-> (A u. B) ~~ 2o))
 
Supremum
 
Syntaxcsup 4564 Extend class notation to include supremum of class A. Here