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Statement List for Metamath Proof Explorer - 6801-6900 - Page 69 of 123
TypeLabelDescription
Statement
 
Theoremexpord2 6801 The power of a positive number smaller than 1 decreases as its exponent increases.
|- (((A e. RR /\ M e. NN0 /\ N e. NN0) /\ (0 < A /\ A < 1)) -> (M < N <-> (A^N) < (A^M)))
 
Theoremexpword2i 6802 Weak ordering relationship for exponentiation. (Contributed by Paul Chapman, 14-Jan-2008.)
|- (((A e. RR /\ M e. NN0 /\ N e. NN0) /\ (0 < A /\ A <_ 1 /\ M < N)) -> (A^N) <_ (A^M))
 
Theoremexpmwordi 6803 Weak mantissa ordering relationship for exponentiation.
|- (((A e. RR /\ B e. RR /\ N e. NN0) /\ (0 <_ A /\ A <_ B)) -> (A^N) <_ (B^N))
 
Theoremexple1 6804 Nonnegative integer exponentiation with a mantissa between 0 and 1 inclusive is less than or equal to 1. (Contributed by Paul Chapman, 29-Dec-2007.)
|- (((A e. RR /\ 0 <_ A /\ A <_ 1) /\ N e. NN0) -> (A^N) <_ 1)
 
Theoremexpubnd 6805 An upper bound on A^N when 2 <_ A.
|- ((A e. RR /\ N e. NN0 /\ 2 <_ A) -> (A^N) <_ ((2^N) x. ((A - 1)^N)))
 
Theoremsqval 6806 Value of the square of a complex number. (Contributed by Raph Levien, 10-Apr-2004.)
|- (A e. CC -> (A^2) = (A x. A))
 
Theoremsqneg 6807 The square of the negative of a number.)
|- (A e. CC -> (-uA^2) = (A^2))
 
Theoremsqcl 6808 Closure of square.
|- (A e. CC -> (A^2) e. CC)
 
Theoremsqmul 6809 Distribution of square over multiplication.
|- ((A e. CC /\ B e. CC) -> ((A x. B)^2) = ((A^2) x. (B^2)))
 
Theoremsqeq0 6810 A number is zero iff its square is zero.
|- (A e. CC -> ((A^2) = 0 <-> A = 0))
 
Theoremsqvali 6811 Value of square. Inference version.
|- A e. CC   =>   |- (A^2) = (A x. A)
 
Theoremsqcli 6812 Closure of square.
|- A e. CC   =>   |- (A^2) e. CC
 
Theoremsqeq0i 6813 A number is zero iff its square is zero.
|- A e. CC   =>   |- ((A^2) = 0 <-> A = 0)
 
Theoremsqmuli 6814 Distribution of square over multiplication.
|- A e. CC   &   |- B e. CC   =>   |- ((A x. B)^2) = ((A^2) x. (B^2))
 
Theoremsqdivi 6815 Distribution of square over division.
|- A e. CC   &   |- B e. CC   &   |- B =/= 0   =>   |- ((A / B)^2) = ((A^2) / (B^2))
 
Theoremsqrecii 6816 Square of reciprocal.
|- A e. CC   &   |- A =/= 0   =>   |- ((1 / A)^2) = (1 / (A^2))
 
Theoremsqne0 6817 A number is nonzero iff its square is nonzero.
|- (A e. CC -> ((A^2) =/= 0 <-> A =/= 0))
 
Theoremresqcl 6818 Closure of the square of a real number.
|- (A e. RR -> (A^2) e. RR)
 
Theoremsqgt0 6819 The square of a non-zero real is positive.
|- ((A e. RR /\ A =/= 0) -> 0 < (A^2))
 
Theoremresqcli 6820 Closure of square in reals.
|- A e. RR   =>   |- (A^2) e. RR
 
Theoremlt2sqi 6821 The square function on nonnegative reals is strictly monotonic.
|- A e. RR   &   |- B e. RR   =>   |- ((0 <_ A /\ 0 <_ B) -> (A < B <-> (A^2) < (B^2)))
 
Theoremle2sqi 6822 The square function on nonnegative reals is monotonic.
|- A e. RR   &   |- B e. RR   =>   |- ((0 <_ A /\ 0 <_ B) -> (A <_ B <-> (A^2) <_ (B^2)))
 
Theoremsq11i 6823 The square function is one-to-one for nonnegative reals.
|- A e. RR   &   |- B e. RR   =>   |- ((0 <_ A /\ 0 <_ B) -> ((A^2) = (B^2) <-> A = B))
 
Theoremsqgt0i 6824 The square of a non-zero real is positive.
|- A e. RR   =>   |- (A =/= 0 -> 0 < (A^2))
 
Theoremsqge0i 6825 A square of a real is nonnegative.
|- A e. RR   =>   |- 0 <_ (A^2)
 
Theoremsq11 6826 The square function is one-to-one for nonnegative reals.
|- (((A e. RR /\ 0 <_ A) /\ (B e. RR /\ 0 <_ B)) -> ((A^2) = (B^2) <-> A = B))
 
Theoremlt2sq 6827 The square function on nonnegative reals is strictly monotonic.
|- (((A e. RR /\ 0 <_ A) /\ (B e. RR /\ 0 <_ B)) -> (A < B <-> (A^2) < (B^2)))
 
Theoremle2sq 6828 The square function on nonnegative reals is monotonic.
|- (((A e. RR /\ 0 <_ A) /\ (B e. RR /\ 0 <_ B)) -> (A <_ B <-> (A^2) <_ (B^2)))
 
Theoremle2sq2 6829 The square of a 'less than or equal to' ordering.
|- (((A e. RR /\ 0 <_ A) /\ (B e. RR /\ A <_ B)) -> (A^2) <_ (B^2))
 
Theoremsqge0 6830 A square of a real is nonnegative.
|- (A e. RR -> 0 <_ (A^2))
 
Theoremsumsqne0i 6831 The sum of two squares is nonzero iff one of its terms is nonzero.
|- A e. RR   &   |- B e. RR   =>   |- ((A =/= 0 \/ B =/= 0) <-> ((A^2) + (B^2)) =/= 0)
 
Theoremsq0 6832 The square of 0 is 0.
|- (0^2) = 0
 
Theoremsq0i 6833 If a number is zero, its square is zero. (Contributed by FL, 10-Dec-2006.)
|- (A = 0 -> (A^2) = 0)
 
Theoremsq1 6834 The square of 1 is 1.
|- (1^2) = 1
 
Theoremsq2 6835 The square of 2 is 4.
|- (2^2) = 4
 
Theoremsq3 6836 The square of 3 is 9.
|- (3^2) = 9
 
Theoremcu2 6837 The cube of 2 is 8.
|- (2^3) = 8
 
Theoremsqlecan 6838 Cancel one factor of a square in a <_ comparison. Unlike lemul1 5973, the common factor A may be zero.
|- (((A e. RR /\ 0 <_ A) /\ (B e. RR /\ 0 <_ B)) -> ((A^2) <_ (B x. A) <-> A <_ B))
 
Theoremsubsq 6839 Factor the difference of two squares.
|- ((A e. CC /\ B e. CC) -> ((A^2) - (B^2)) = ((A + B) x. (A - B)))
 
Theoremsubsq2 6840 Express the difference of the squares of two numbers as a polynomial in the difference of the numbers.
|- ((A e. CC /\ B e. CC) -> ((A^2) - (B^2)) = (((A - B)^2) + ((2 x. B) x. (A - B))))
 
Theorembinom2i 6841 The square of a binomial.
|- A e. CC   &   |- B e. CC   =>   |- ((A + B)^2) = (((A^2) + (2 x. (A x. B))) + (B^2))
 
Theorembinom2aiOLD 6842 Product of sum and difference.
|- A e. CC   &   |- B e. CC   =>   |- ((A + B) x. (A - B)) = ((A^2) - (B^2))
 
Theoremsubsqi 6843 Factor the difference of two squares.
|- A e. CC   &   |- B e. CC   =>   |- ((A^2) - (B^2)) = ((A + B) x. (A - B))
 
Theoremsqeqori 6844 The squares of two complex numbers are equal iff one number equals the other or its negative. Lemma 15-4.7 of [Gleason] p. 311 and its converse.
|- A e. CC   &   |- B e. CC   =>   |- ((A^2) = (B^2) <-> (A = B \/ A = -uB))
 
Theoremsubsq0i 6845 The two solutions to the difference of squares set equal to zero.
|- A e. CC   &   |- B e. CC   =>   |- (((A^2) - (B^2)) = 0 <-> (A = B \/ A = -uB))
 
Theoremsqeqor 6846 The squares of two complex numbers are equal iff one number equals the other or its negative. Lemma 15-4.7 of [Gleason] p. 311 and its converse. (Contributed by Paul Chapman, 15-Mar-2008.)
|- ((A e. CC /\ B e. CC) -> ((A^2) = (B^2) <-> (A = B \/ A = -uB)))
 
Theorembinom2 6847 The square of a binomial. (Contributed by FL, 10-Dec-2006.)
|- ((A e. CC /\ B e. CC) -> ((A + B)^2) = (((A^2) + (2 x. (A x. B))) + (B^2)))
 
Theoremsq01 6848 If a complex number equals its square, it must be 0 or 1.
|- (A e. CC -> ((A^2) = A <-> (A = 0 \/ A = 1)))
 
Theorembernneq 6849 Bernoulli's inequality, due to Johan Bernoulli (1667-1748).
|- ((A e. RR /\ N e. NN0 /\ -u1 <_ A) -> (1 + (A x. N)) <_ ((1 + A)^N))
 
TheorembernneqOLD 6850 Bernoulli's inequality, due to Johan Bernoulli (1667-1748).
|- ((A e. RR /\ N e. NN0 /\ -u1 <_ A) -> (1 + (A x. N)) <_ ((1 + A)^N))
 
Theorembernneq2 6851 Variation of Bernoulli's inequality bernneq 6849.
|- ((A e. RR /\ N e. NN0 /\ 0 <_ A) -> (((A - 1) x. N) + 1) <_ (A^N))
 
Theoremexpnbnd 6852 Exponentiation with a mantissa greater than 1 has no upper bound.
|- ((A e. RR /\ B e. RR /\ 1 < B) -> E.k e. NN A < (B^k))
 
Theoremexpnlbnd 6853 The reciprocal of exponentiation with a mantissa greater than 1 has no lower bound.
|- ((A e. RR+ /\ B e. RR /\ 1 < B) -> E.k e. NN (1 / (B^k)) < A)
 
Theoremexpnlbnd2 6854 The reciprocal of exponentiation with a mantissa greater than 1 has no lower bound.
|- ((A e. RR+ /\ B e. RR /\ 1 < B) -> E.j e. NN A.k e. NN (j <_ k -> (1 / (B^k)) < A))
 
Theoremdigit2 6855 Two ways to express the K th digit in the decimal (when base B = 10) expansion of a number A. K = 1 corresponds to the first digit after the decimal point.
|- ((A e. RR /\ B e. NN /\ K e. NN) -> ((|_` ((B^K) x. A)) mod B) = ((|_` ((B^K) x. A)) - (B x. (|_` ((B^(K - 1)) x. A)))))
 
Theoremdigit1 6856 Two ways to express the K th digit in the decimal expansion of a number A (when base B = 10). K = 1 corresponds to the first digit after the decimal point.
|- ((A e. RR /\ B e. NN /\ K e. NN) -> ((|_` ((B^K) x. A)) mod B) = (((|_`
 ((B^K) x. A)) mod (B^K)) - ((B x. (|_` ((B^(K - 1)) x. A))) mod (B^K))))
 
Discriminant
 
Theoremdiscrlem1 6857 Lemma for discriminant theorem.
 
Theoremdiscrlem2 6858 Lemma for discriminant theorem.
 
Theoremdiscrlem3 6859 Lemma for discriminant theorem.
 
Theoremdiscrlem 6860 If a quadratic polynomial with real coefficients is nonnegative for all values, then its discriminant is non-positive. The antecedent 0 <_ A is redundant but simplifies the proof.
|- A e. RR   &   |- B e. RR   &   |- C e. RR   &   |- A.x e. RR 0 <_ (((A x. (x^2)) + (B x. x)) + C)   =>   |- (0 <_ A -> ((B^2) - (4 x. (A x. C))) <_ 0)
 
More natural number properties
 
Theoremnnsqcli 6861 The square of a natural number is a natural number.
|- N e. NN   =>   |- (N^2) e. NN
 
Theoremnnlesqi 6862 A natural number is less than or equal to its square.
|- N e. NN   =>   |- N <_ (N^2)
 
Theoremnnesqi 6863 A natural number is even iff its square is even.
|- N e. NN   =>   |- ((N / 2) e. NN <-> ((N^2) / 2) e. NN)
 
Ordered pair theorem for nonnegative integers
 
Theoremnn0le2msqi 6864 The square function on nonnegative integers is monotonic. (Contributed by Raph Levien, 10-Dec-2002.)
|- A e. NN0   &   |- B e. NN0   =>   |- (A <_ B <-> (A x. A) <_ (B x. B))
 
Theoremnn0opthlem1 6865 A rather pretty lemma for nn0opthi 6867. (Contributed by Raph Levien, 10-Dec-2002.)
|- A e. NN0   &   |- C e. NN0   =>   |- (A < C <-> ((A x. A) + (2 x. A)) < (C x. C))
 
Theoremnn0opthlem2 6866 Lemma for nn0opthi 6867.
 
Theoremnn0opthi 6867 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. We can represent an ordered pair of nonnegative integers A and B by (((A + B) x. (A + B)) + B). If two such ordered pairs are equal, their first elements are equal and their second elements are equal. Contrast this ordered pair representation with the standard one df-op 2474 that works for any set. (Contributed by Raph Levien, 10-Dec-2002.)
|- A e. NN0   &   |- B e. NN0   &   |- C e. NN0   &   |- D e. NN0   =>   |- ((((A + B) x. (A + B)) + B) = (((C + D) x. (C + D)) + D) <-> (A = C /\ B = D))
 
Theoremnn0opth2i 6868 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. See nn0opthi 6867.
|- A e. NN0   &   |- B e. NN0   &   |- C e. NN0   &   |- D e. NN0   =>   |- ((((A + B)^2) + B) = (((C + D)^2) + D) <-> (A = C /\ B = D))
 
Theoremnn0opth2 6869 An ordered pair theorem for nonnegative integers. Theorem 17.3 of [Quine] p. 124. See nn0opthi 6867.
|- (((A e. NN0 /\ B e. NN0) /\ (C e. NN0 /\ D e. NN0)) -> ((((A + B)^2) + B) = (((C + D)^2) + D) <-> (A = C /\ B = D)))
 
Square root
 
Syntaxcsqr 6870 Extend class notation to include positive square root of a positive real number.
class sqr
 
Definitiondf-sqr 6871 Define a function whose value is the square root of a nonnegative real number. The square root of x is the supremum of all reals whose square is less than x. See sqrcli 6901 for its closure, sqrval 6872 for its value, sqrsqi 6921 and sqsqri 6922 for its relationship to squares, and sqr11i 6904 for uniqueness.
|- sqr = {<.x, y>. | ((x e. RR /\ 0 <_ x) /\ y = sup({z e. RR | (0 <_ z /\ (z x. z) <_ x)}, RR, < ))}
 
Theoremsqrval 6872 Value of square root function.
|- ((A e. RR /\ 0 <_ A) -> (sqr` A) = sup({x e. RR | (0 <_ x /\ (x x. x) <_ A)}, RR, < ))
 
Theoremsqr0 6873 Square root of zero.
|- (sqr` 0) = 0
 
Theoremsqrlem1 6874 Lemma for square root theorem.
 
Theoremsqrlem2 6875 Lemma for square root theorem.
 
Theoremsqrlem3 6876 Lemma for square root theorem.
 
Theoremsqrlem4 6877 Lemma for square root theorem.
 
Theoremsqrlem5 6878 Lemma for square root theorem.
 
Theoremsqrlem6 6879 Lemma for square root theorem.
 
Theoremsqrlem7 6880 Lemma for square root theorem.
 
Theoremsqrlem8 6881 Lemma for square root theorem.
 
Theoremsqrlem9 6882 Lemma for square root theorem.
 
Theoremsqrlem10 6883 Lemma for square root theorem.
 
Theoremsqrlem11 6884 Lemma for square root theorem.
 
Theoremsqrlem12 6885 Lemma for square root theorem.
 
Theoremsqrlem13 6886 Lemma for square root theorem.
 
Theoremsqrlem14 6887 Lemma for square root theorem.
 
Theoremsqrlem15 6888 Lemma for square root theorem.
 
Theoremsqrlem16 6889 Lemma for square root theorem.
 
Theoremsqrlem17 6890 Lemma for square root theorem.
 
Theoremsqrlem18 6891 Lemma for square root theorem.
 
Theoremsqrlem19 6892 Lemma for square root theorem.
 
Theoremsqrlem20 6893 Lemma for square root theorem.
 
Theoremsqrlem21 6894 Lemma for square root theorem.
 
Theoremsqrlem22 6895 Lemma for square root theorem.
 
Theoremsqrlem23 6896 Lemma for square root theorem.
 
Theoremsqrlem24 6897 Lemma for square root closure.
 
Theoremsqrgt0ii 6898 The square root of a positive real is positive.
|- A e. RR   &   |- 0 < A   =>   |- 0 < (sqr`
 A)
 
Theoremsqrlem26 6899 Lemma for square root theorem.
 
Theoremsqrthi 6900 Square root theorem. Theorem I.35 of [Apostol] p. 29.

(A bit of trivia: This theorem was added to the database before the number 2 was defined and before exponents were defined. Thus you will see (1 + 1) and (x x. x) throughout its lemmas.)

|- A e. RR   =>   |- (0 <_ A -> ((sqr` A) x. (sqr` A)) = A)

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