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Statement List for Metamath Proof Explorer - 9501-9600 - Page 96 of 107
TypeLabelDescription
Statement
 
Theoremcmbr3 9501 Alternate definition for the commutes relation. Lemma 3 of [Kalmbach] p. 23.
|- A e. CH   &   |- B e. CH   =>   |- (A C_H B <-> (A i^i ((_|_`
 A) vH B)) = (A i^i B))
 
Theoremcmbr4 9502 Alternate definition for the commutes relation.
|- A e. CH   &   |- B e. CH   =>   |- (A C_H B <-> (A i^i ((_|_`
 A) vH B)) (_ B)
 
Theoremlecm 9503 Comparable Hilbert lattice elements commute. Theorem 2.3(iii) of [Beran] p. 40.
|- A e. CH   &   |- B e. CH   =>   |- (A (_ B -> A C_H B)
 
Theoremlecmi 9504 Comparable Hilbert lattice elements commute. Theorem 2.3(iii) of [Beran] p. 40.
|- A e. CH   &   |- B e. CH   &   |- A (_ B   =>   |- A C_H B
 
Theoremcmj1 9505 A Hilbert lattice element commutes with its join.
|- A e. CH   &   |- B e. CH   =>   |- A C_H (A vH B)
 
Theoremcmj2 9506 A Hilbert lattice element commutes with its join.
|- A e. CH   &   |- B e. CH   =>   |- B C_H (A vH B)
 
Theoremcmm1 9507 A Hilbert lattice element commutes with its meet.
|- A e. CH   &   |- B e. CH   =>   |- A C_H (A i^i B)
 
Theoremcmm2 9508 A Hilbert lattice element commutes with its meet.
|- A e. CH   &   |- B e. CH   =>   |- B C_H (A i^i B)
 
Theoremcmbr3t 9509 Alternate definition for the commutes relation. Lemma 3 of [Kalmbach] p. 23.
|- ((A e. CH /\ B e. CH) -> (A C_H B <-> (A i^i ((_|_` A) vH B)) = (A i^i B)))
 
Theoremcm0t 9510 The zero Hilbert lattice element commutes with every element.
|- (A e. CH -> 0H C_H A)
 
Theoremcmid 9511 The commutes relation is reflexive.
|- A e. CH   =>   |- A C_H A
 
Theorempjoml2t 9512 Variation of orthomodular law. Definition in [Kalmbach] p. 22.
|- ((A e. CH /\ B e. CH /\ A (_ B) -> (A vH ((_|_` A) i^i B)) = B)
 
Theorempjoml3t 9513 Variation of orthomodular law.
|- ((A e. CH /\ B e. CH) -> (B (_ A -> (A i^i ((_|_`
 A) vH B)) = B))
 
Theorempjoml5t 9514 The orthomodular law. Remark in [Kalmbach] p. 22.
|- ((A e. CH /\ B e. CH) -> (A vH ((_|_`
 A) i^i (A vH B))) = (A vH B))
 
Theoremcmcmt 9515 Commutation is symmetric. Theorem 2(v) of [Kalmbach] p. 22.
|- ((A e. CH /\ B e. CH) -> (A C_H B <-> B C_H A))
 
Theoremcmcm3t 9516 Commutation with orthocomplement. Remark in [Kalmbach] p. 23.
|- ((A e. CH /\ B e. CH) -> (A C_H B <-> (_|_` A) C_H B))
 
Theoremcmcm2t 9517 Commutation with orthocomplement. Theorem 2.3(i) of [Beran] p. 39.
|- ((A e. CH /\ B e. CH) -> (A C_H B <-> A C_H (_|_` B)))
 
Theoremlecmt 9518 Comparable Hilbert lattice elements commute. Theorem 2.3(iii) of [Beran] p. 40.
|- ((A e. CH /\ B e. CH /\ A (_ B) -> A C_H B)
 
Foulis-Holland theorem
 
Theoremfh1t 9519 Foulis-Holland Theorem. If any 2 pairs in a triple of orthomodular lattice elements commute, the triple is distributive. First of two parts. Theorem 5 of [Kalmbach] p. 25.
|- (((A e. CH /\ B e. CH /\ C e. CH) /\ (A C_H B /\ A C_H C)) -> (A i^i (B vH C)) = ((A i^i B) vH (A i^i C)))
 
Theoremfh2t 9520 Foulis-Holland Theorem. If any 2 pairs in a triple of orthomodular lattice elements commute, the triple is distributive. Second of two parts. Theorem 5 of [Kalmbach] p. 25.
|- (((A e. CH /\ B e. CH /\ C e. CH) /\ (B C_H A /\ B C_H C)) -> (A i^i (B vH C)) = ((A i^i B) vH (A i^i C)))
 
Theoremcm2jt 9521 A lattice element that commutes with two others also commutes with their join. Theorem 4.2 of [Beran] p. 49.
|- (((A e. CH /\ B e. CH /\ C e. CH) /\ (A C_H B /\ A C_H C)) -> A C_H (B vH C))
 
Theoremfh1 9522 Foulis-Holland Theorem. If any 2 pairs in a triple of orthomodular lattice elements commute, the triple is distributive. First of two parts. Theorem 5 of [Kalmbach] p. 25.
|- A e. CH   &   |- B e. CH   &   |- C e. CH   &   |- A C_H B   &   |- A C_H C   =>   |- (A i^i (B vH C)) = ((A i^i B) vH (A i^i C))
 
Theoremfh2 9523 Foulis-Holland Theorem. If any 2 pairs in a triple of orthomodular lattice elements commute, the triple is distributive. Second of two parts. Theorem 5 of [Kalmbach] p. 25.
|- A e. CH   &   |- B e. CH   &   |- C e. CH   &   |- A C_H B   &   |- A C_H C   =>   |- (B i^i (A vH C)) = ((B i^i A) vH (B i^i C))
 
Theoremfh3 9524 Variation of the Foulis-Holland Theorem.
|- A e. CH   &   |- B e. CH   &   |- C e. CH   &   |- A C_H B   &   |- A C_H C   =>   |- (A vH (B i^i C)) = ((A vH B) i^i (A vH C))
 
Theoremfh4 9525 Variation of the Foulis-Holland Theorem.
|- A e. CH   &   |- B e. CH   &   |- C e. CH   &   |- A C_H B   &   |- A C_H C   =>   |- (B vH (A i^i C)) = ((B vH A) i^i (B vH C))
 
Quantum Logic Explorer axioms
 
Theoremqlax1 9526 One of the equations showing CH is an ortholattice. (This corresponds to axiom "ax-1" in the Quantum Logic Explorer.)
|- A e. CH   =>   |- A = (_|_`
 (_|_` A))
 
Theoremqlax2 9527 One of the equations showing CH is an ortholattice. (This corresponds to axiom "ax-2" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   =>   |- (A vH B) = (B vH A)
 
Theoremqlax3 9528 One of the equations showing CH is an ortholattice. (This corresponds to axiom "ax-3" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   &   |- C e. CH   =>   |- ((A vH B) vH C) = (A vH (B vH C))
 
Theoremqlax4 9529 One of the equations showing CH is an ortholattice. (This corresponds to axiom "ax-4" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   =>   |- (A vH (B vH (_|_` B))) = (B vH (_|_` B))
 
Theoremqlax5 9530 One of the equations showing CH is an ortholattice. (This corresponds to axiom "ax-5" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   =>   |- (A vH (_|_` ((_|_` A) vH B))) = A
 
Theoremqlaxr1 9531 One of the conditions showing CH is an ortholattice. (This corresponds to axiom "ax-r1" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   &   |- A = B   =>   |- B = A
 
Theoremqlaxr2 9532 One of the conditions showing CH is an ortholattice. (This corresponds to axiom "ax-r2" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   &   |- C e. CH   &   |- A = B   &   |- B = C   =>   |- A = C
 
Theoremqlaxr4 9533 One of the conditions showing CH is an ortholattice. (This corresponds to axiom "ax-r4" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   &   |- A = B   =>   |- (_|_` A) = (_|_` B)
 
Theoremqlaxr5 9534 One of the conditions showing CH is an ortholattice. (This corresponds to axiom "ax-r5" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   &   |- C e. CH   &   |- A = B   =>   |- (A vH C) = (B vH C)
 
Theoremqlaxr3 9535 A variation of the orthomodular law, showing CH is an orthomodular lattice. (This corresponds to axiom "ax-r3" in the Quantum Logic Explorer.)
|- A e. CH   &   |- B e. CH   &   |- C e. CH   &   |- (C vH (_|_` C)) = ((_|_` ((_|_` A) vH (_|_` B))) vH (_|_` (A vH B)))   =>   |- A = B
 
Orthogonal subspaces
 
Theoremosumlem1 9536 Lemma for osum 9544.
 
Theoremosumlem2 9537 Lemma for osum 9544.
 
Theoremosumlem3 9538 Lemma for osum 9544.
 
Theoremosumlem4 9539 Lemma for osum 9544.
 
Theoremosumlem5 9540 Lemma for osum 9544.
 
Theoremosumlem6 9541 Lemma for osum 9544.
 
Theoremosumlem7 9542 Lemma for osum 9544.
 
Theoremosumlem8 9543 Lemma for osum 9544.
 
Theoremosum 9544 If two closed subspaces of a Hilbert space are orthogonal, their subspace sum equals their subspace join. Lemma 3 of [Kalmbach] p. 67. Note that the Axiom of Choice is used for this proof (in osumlem5 9540 and via pjpjtht 9214 in osumlem7 9542).
|- A e. CH   &   |- B e. CH   =>   |- (A (_ (_|_` B) -> (A +H B) = (A vH B))
 
Theoremosumcor 9545 Corollary of osum 9544.
|- A e. CH   &   |- B e. CH   =>   |- ((A i^i B) +H (A i^i (_|_` B))) = ((A i^i B) vH (A i^i (_|_` B)))
 
Theoremosumt 9546 If two closed subspaces of a Hilbert space are orthogonal, their subspace sum equals their subspace join. Lemma 3 of [Kalmbach] p. 67.
|- ((A e. CH /\ B e. CH /\ A (_ (_|_`
 B)) -> (A +H B) = (A vH B))
 
Theoremchsot 9547 The subspace sum of a closed subspace and its complement is all of Hilbert space.
|- (A e. CH -> (A +H (_|_` A)) = H~)
 
Theoremosumcor2 9548 Corollary of osum 9544, showing it holds under the weaker hypothesis that A and B commute.
|- A e. CH   &   |- B e. CH   =>   |- (A C_H B -> (A +H B) = (A vH B))
 
Theoremspansnj 9549 The subspace sum of a closed subspace and a one-dimensional subspace equals their join. (Proof suggested by Eric Schechter 1-Jun-2004.)
|- A e. CH   &   |- B e. H~   =>   |- (A +H (span` {B})) = (A vH (span` {B}))
 
Theoremspansnjt 9550 The subspace sum of a closed subspace and a one-dimensional subspace equals their join.
|- ((A e. CH /\ B e. H~) -> (A +H (span` {B})) = (A vH (span` {B})))
 
Theoremspansnsclt 9551 The subspace sum of a closed subspace and a one-dimensional subspace is closed.
|- ((A e. CH /\ B e. H~) -> (A +H (span` {B})) e. CH)
 
Theoremsumspansnt 9552 The sum of two vectors belong to the span of one of them iff the other vector also belongs.
|- ((A e. H~ /\ B e. H~) -> ((A +h B) e. (span` {A}) <-> B e. (span` {A})))
 
Theoremspansnm0 9553 The meet of different one-dimensional subspaces is the zero subspace.
|- A e. H~   &   |- B e. H~   =>   |- (-. A e. (span` {B}) -> ((span` {A}) i^i (span` {B})) = 0H)
 
Theoremnonbool 9554 A Hilbert lattice with two or more dimensions fails the distributive law and therefore cannot be a Boolean algebra. This counterexample demonstrates a condition where ((H i^i F) vH (H i^i G)) = 0H but (H i^i (F vH G)) =/= 0H. The antecedent specifies that the vectors A and B are nonzero and non-colinear. The last three hypotheses assign one-dimensional subspaces to F, G, and H.
|- A e. H~   &   |- B e. H~   &   |- F = (span` {A})   &   |- G = (span` {B}