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Theorem qdass 3802
Description: Two ways to write an unordered quadruple. (Contributed by Mario Carneiro, 5-Jan-2016.)
Assertion
Ref Expression
qdass  |-  ( { A ,  B }  u.  { C ,  D } )  =  ( { A ,  B ,  C }  u.  { D } )

Proof of Theorem qdass
StepHypRef Expression
1 unass 3408 . 2  |-  ( ( { A ,  B }  u.  { C } )  u.  { D } )  =  ( { A ,  B }  u.  ( { C }  u.  { D } ) )
2 df-tp 3724 . . 3  |-  { A ,  B ,  C }  =  ( { A ,  B }  u.  { C } )
32uneq1i 3401 . 2  |-  ( { A ,  B ,  C }  u.  { D } )  =  ( ( { A ,  B }  u.  { C } )  u.  { D } )
4 df-pr 3723 . . 3  |-  { C ,  D }  =  ( { C }  u.  { D } )
54uneq2i 3402 . 2  |-  ( { A ,  B }  u.  { C ,  D } )  =  ( { A ,  B }  u.  ( { C }  u.  { D } ) )
61, 3, 53eqtr4ri 2389 1  |-  ( { A ,  B }  u.  { C ,  D } )  =  ( { A ,  B ,  C }  u.  { D } )
Colors of variables: wff set class
Syntax hints:    = wceq 1642    u. cun 3226   {csn 3716   {cpr 3717   {ctp 3718
This theorem is referenced by:  ex-pw  20922
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-3 7  ax-mp 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1930  ax-ext 2339
This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2345  df-cleq 2351  df-clel 2354  df-nfc 2483  df-v 2866  df-un 3233  df-pr 3723  df-tp 3724
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