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Unicode version

Theorem sb7f 1339
Description: This version of dfsb7 1338 does not require that ph and z be distinct. This permits it to be used as a definition for substitution in a formalization that omits the logically redundant axiom ax-17 969 i.e. that doesn't have the concept of a variable not occurring in a wff. (df-sb 1170 is also suitable, but its mixing of free and bound variables is distasteful to some logicians.)
Hypothesis
Ref Expression
sb7f.1 |- (ph -> A.zph)
Assertion
Ref Expression
sb7f |- ([y / x]ph <-> E.z(z = y /\ E.x(x = z /\ ph)))
Distinct variable groups:   x,z   y,z

Proof of Theorem sb7f
StepHypRef Expression
1 dfsb7 1338 . 2 |- ([y / x]ph <-> E.w(w = y /\ E.x(x = w /\ ph)))
2 ax-17 969 . . . 4 |- (w = y -> A.z w = y)
3 ax-17 969 . . . . . 6 |- (x = w -> A.z x = w)
4 sb7f.1 . . . . . 6 |- (ph -> A.zph)
53, 4hban 1007 . . . . 5 |- ((x = w /\ ph) -> A.z(x = w /\ ph))
65hbex 1004 . . . 4 |- (E.x(x = w /\ ph) -> A.zE.x(x = w /\ ph))
72, 6hban 1007 . . 3 |- ((w = y /\ E.x(x = w /\ ph)) -> A.z(w = y /\ E.x(x = w /\ ph)))
8 ax-17 969 . . 3 |- ((z = y /\ E.x(x = z /\ ph)) -> A.w(z = y /\ E.x(x = z /\ ph)))
9 equequ1 1132 . . . 4 |- (w = z -> (w = y <-> z = y))
10 equequ2 1133 . . . . . 6 |- (w = z -> (x = w <-> x = z))
1110anbi1d 616 . . . . 5 |- (w = z -> ((x = w /\ ph) <-> (x = z /\ ph)))
1211exbidv 1277 . . . 4 |- (w = z -> (E.x(x = w /\ ph) <-> E.x(x = z /\ ph)))
139, 12anbi12d 627 . . 3 |- (w = z -> ((w = y /\ E.x(x = w /\ ph)) <-> (z = y /\ E.x(x = z /\ ph))))
147, 8, 13cbvex 1164 . 2 |- (E.w(w = y /\ E.x(x = w /\ ph)) <-> E.z(z = y /\ E.x(x = z /\ ph)))
151, 14bitr 173 1 |- ([y / x]ph <-> E.z(z = y /\ E.x(x = z /\ ph)))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 146   /\ wa 223  A.wal 952   = wceq 954  E.wex 978  [wsbc 1168
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 960  ax-gen 961  ax-8 962  ax-9 963  ax-10 964  ax-11 965  ax-12 966  ax-17 969  ax-4 971  ax-5o 973  ax-6o 976  ax-9o 1121  ax-10o 1138  ax-16 1208  ax-11o 1216
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 979  df-sb 1170
Copyright terms: Public domain