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Theorem sban 1962
Description: Conjunction inside and outside of a substitution are equivalent. (Contributed by NM, 5-Aug-1993.)
Assertion
Ref Expression
sban  |-  ( [ y  /  x ]
( ph  /\  ps )  <->  ( [ y  /  x ] ph  /\  [ y  /  x ] ps ) )

Proof of Theorem sban
StepHypRef Expression
1 sbn 1955 . . 3  |-  ( [ y  /  x ]  -.  ( ph  ->  -.  ps )  <->  -.  [ y  /  x ] ( ph  ->  -.  ps ) )
2 sbim 1958 . . . 4  |-  ( [ y  /  x ]
( ph  ->  -.  ps ) 
<->  ( [ y  /  x ] ph  ->  [ y  /  x ]  -.  ps ) )
3 sbn 1955 . . . . 5  |-  ( [ y  /  x ]  -.  ps  <->  -.  [ y  /  x ] ps )
43imbi2i 305 . . . 4  |-  ( ( [ y  /  x ] ph  ->  [ y  /  x ]  -.  ps ) 
<->  ( [ y  /  x ] ph  ->  -.  [ y  /  x ] ps ) )
52, 4bitri 242 . . 3  |-  ( [ y  /  x ]
( ph  ->  -.  ps ) 
<->  ( [ y  /  x ] ph  ->  -.  [ y  /  x ] ps ) )
61, 5xchbinx 303 . 2  |-  ( [ y  /  x ]  -.  ( ph  ->  -.  ps )  <->  -.  ( [
y  /  x ] ph  ->  -.  [ y  /  x ] ps )
)
7 df-an 362 . . 3  |-  ( (
ph  /\  ps )  <->  -.  ( ph  ->  -.  ps ) )
87sbbii 1886 . 2  |-  ( [ y  /  x ]
( ph  /\  ps )  <->  [ y  /  x ]  -.  ( ph  ->  -.  ps ) )
9 df-an 362 . 2  |-  ( ( [ y  /  x ] ph  /\  [ y  /  x ] ps ) 
<->  -.  ( [ y  /  x ] ph  ->  -.  [ y  /  x ] ps ) )
106, 8, 93bitr4i 270 1  |-  ( [ y  /  x ]
( ph  /\  ps )  <->  ( [ y  /  x ] ph  /\  [ y  /  x ] ps ) )
Colors of variables: wff set class
Syntax hints:   -. wn 5    -> wi 6    <-> wb 178    /\ wa 360   [wsb 1883
This theorem is referenced by:  sb3an  1963  sbbi  1964  sbabel  2418  cbvreu  2716  sbcan  2977  sbcang  2978  rmo3  3020  inab  3378  difab  3379  exss  4173  inopab  4769  ballotlemodife  22982  sb5ALT  27304  2uasbanh  27343  2uasbanhVD  27700  sb5ALTVD  27702
This theorem was proved from axioms:  ax-1 7  ax-2 8  ax-3 9  ax-mp 10  ax-5 1533  ax-6 1534  ax-7 1535  ax-gen 1536  ax-8 1623  ax-11 1624  ax-17 1628  ax-12o 1664  ax-10 1678  ax-9 1684  ax-4 1692
This theorem depends on definitions:  df-bi 179  df-an 362  df-tru 1315  df-ex 1538  df-nf 1540  df-sb 1884
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