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Theorem sbc5g 1950
Description: An equivalence for class substitution.
Assertion
Ref Expression
sbc5g |- (A e. B -> ([A / x]ph <-> E.x(x = A /\ ph)))
Distinct variable group:   x,A

Proof of Theorem sbc5g
StepHypRef Expression
1 biimt 730 . . . . . 6 |- (A e. V -> (ph <-> (A e. V -> ph)))
21anbi2d 615 . . . . 5 |- (A e. V -> ((x = A /\ ph) <-> (x = A /\ (A e. V -> ph))))
32exbidv 1277 . . . 4 |- (A e. V -> (E.x(x = A /\ ph) <-> E.x(x = A /\ (A e. V -> ph))))
4 biimt 730 . . . 4 |- (A e. V -> (E.x(x = A /\ ph) <-> (A e. V -> E.x(x = A /\ ph))))
5 ax-17 969 . . . . . 6 |- (y e. A -> A.x y e. A)
65hbsbc1 1945 . . . . 5 |- ((A e. V -> [A / x]ph) -> A.x(A e. V -> [A / x]ph))
7 sbceq1a 1940 . . . . . 6 |- (x = A -> (ph <-> [A / x]ph))
87imbi2d 611 . . . . 5 |- (x = A -> ((A e. V -> ph) <-> (A e. V -> [A / x]ph)))
96, 8ceqsexg 1883 . . . 4 |- (A e. V -> (E.x(x = A /\ (A e. V -> ph)) <-> (A e. V -> [A / x]ph)))
103, 4, 93bitr3rd 548 . . 3 |- (A e. V -> ((A e. V -> [A / x]ph) <-> (A e. V -> E.x(x = A /\ ph))))
1110pm5.74rd 587 . 2 |- (A e. V -> (A e. V -> ([A / x]ph <-> E.x(x = A /\ ph))))
12 elisset 1813 . 2 |- (A e. B -> A e. V)
1311, 12, 12sylc 68 1 |- (A e. B -> ([A / x]ph <-> E.x(x = A /\ ph)))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 146   /\ wa 223   = wceq 954   e. wcel 956  E.wex 978  [wsbc 1168  Vcvv 1807
This theorem is referenced by:  sbc5 1952  sbc2or 1954  sbciegft 1955  sbcgf 1982  sbccomglem 1984
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 960  ax-gen 961  ax-8 962  ax-10 964  ax-12 966  ax-17 969  ax-4 971  ax-5o 973  ax-6o 976  ax-9o 1121  ax-10o 1138  ax-16 1208  ax-11o 1216  ax-ext 1457
This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 979  df-sb 1170  df-clab 1462  df-cleq 1467  df-clel 1470  df-v 1808  df-sbc 1938
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