Proof of Theorem ax11v2
| Step | Hyp | Ref
| Expression |
| 1 | | a9e 1123 |
. 2
⊢ ∃z z = y |
| 2 | | ax11v2.1 |
. . . . 5
⊢ (x =
z → (φ → ∀x(x = z → φ))) |
| 3 | | equequ2 1133 |
. . . . . . 7
⊢ (z =
y → (x = z ↔
x = y)) |
| 4 | 3 | adantl 388 |
. . . . . 6
⊢ ((¬ ∀x x = y ⋀ z =
y) → (x = z ↔
x = y)) |
| 5 | | dveeq2 1210 |
. . . . . . . . 9
⊢ (¬ ∀x x = y → (z =
y → ∀x z = y)) |
| 6 | 5 | imp 350 |
. . . . . . . 8
⊢ ((¬ ∀x x = y ⋀ z =
y) → ∀x z = y) |
| 7 | | hba1 1001 |
. . . . . . . . 9
⊢ (∀x z = y → ∀x∀x
z = y) |
| 8 | 3 | imbi1d 612 |
. . . . . . . . . 10
⊢ (z =
y → ((x = z →
φ) ↔ (x = y →
φ))) |
| 9 | 8 | a4s 982 |
. . . . . . . . 9
⊢ (∀x z = y → ((x =
z → φ) ↔ (x = y →
φ))) |
| 10 | 7, 9 | albid 1102 |
. . . . . . . 8
⊢ (∀x z = y → (∀x(x = z → φ)
↔ ∀x(x = y →
φ))) |
| 11 | 6, 10 | syl 10 |
. . . . . . 7
⊢ ((¬ ∀x x = y ⋀ z =
y) → (∀x(x = z → φ)
↔ ∀x(x = y →
φ))) |
| 12 | 11 | imbi2d 611 |
. . . . . 6
⊢ ((¬ ∀x x = y ⋀ z =
y) → ((φ → ∀x(x = z → φ))
↔ (φ → ∀x(x = y → φ)))) |
| 13 | 4, 12 | imbi12d 625 |
. . . . 5
⊢ ((¬ ∀x x = y ⋀ z =
y) → ((x = z →
(φ → ∀x(x = z → φ))) ↔ (x = y →
(φ → ∀x(x = y → φ))))) |
| 14 | 2, 13 | mpbii 193 |
. . . 4
⊢ ((¬ ∀x x = y ⋀ z =
y) → (x = y →
(φ → ∀x(x = y → φ)))) |
| 15 | 14 | ex 373 |
. . 3
⊢ (¬ ∀x x = y → (z =
y → (x = y →
(φ → ∀x(x = y → φ))))) |
| 16 | 15 | 19.23adv 1212 |
. 2
⊢ (¬ ∀x x = y → (∃z z = y → (x =
y → (φ → ∀x(x = y → φ))))) |
| 17 | 1, 16 | mpi 44 |
1
⊢ (¬ ∀x x = y → (x =
y → (φ → ∀x(x = y → φ)))) |