Proof of Theorem axacndlem2
| Step | Hyp | Ref
| Expression |
| 1 | | hbae 1141 |
. . 3
⊢ (∀x x = z → ∀y∀x
x = z) |
| 2 | | hbae 1141 |
. . . 4
⊢ (∀x x = z → ∀z∀x
x = z) |
| 3 | | nd1 4910 |
. . . . . 6
⊢ (∀x x = z → ¬ ∀x z ∈
w) |
| 4 | 3 | pm2.21d 78 |
. . . . 5
⊢ (∀x x = z → (∀x z ∈
w → ∃w∀y(∃w((y ∈
z ⋀ z ∈ w)
⋀ (y ∈ w ⋀ w
∈ x)) ↔ y = w))) |
| 5 | | pm3.27 323 |
. . . . . 6
⊢ ((y
∈ z ⋀ z ∈ w)
→ z ∈ w) |
| 6 | 5 | 19.20i 989 |
. . . . 5
⊢ (∀x(y ∈
z ⋀ z ∈ w)
→ ∀x z ∈ w) |
| 7 | 4, 6 | syl5 21 |
. . . 4
⊢ (∀x x = z → (∀x(y ∈
z ⋀ z ∈ w)
→ ∃w∀y(∃w((y ∈
z ⋀ z ∈ w)
⋀ (y ∈ w ⋀ w
∈ x)) ↔ y = w))) |
| 8 | 2, 7 | 19.21ai 995 |
. . 3
⊢ (∀x x = z → ∀z(∀x(y ∈
z ⋀ z ∈ w)
→ ∃w∀y(∃w((y ∈
z ⋀ z ∈ w)
⋀ (y ∈ w ⋀ w
∈ x)) ↔ y = w))) |
| 9 | 1, 8 | 19.21ai 995 |
. 2
⊢ (∀x x = z → ∀y∀z(∀x(y ∈
z ⋀ z ∈ w)
→ ∃w∀y(∃w((y ∈
z ⋀ z ∈ w)
⋀ (y ∈ w ⋀ w
∈ x)) ↔ y = w))) |
| 10 | | 19.8a 1025 |
. 2
⊢ (∀y∀z(∀x(y ∈
z ⋀ z ∈ w)
→ ∃w∀y(∃w((y ∈
z ⋀ z ∈ w)
⋀ (y ∈ w ⋀ w
∈ x)) ↔ y = w)) →
∃x∀y∀z(∀x(y ∈
z ⋀ z ∈ w)
→ ∃w∀y(∃w((y ∈
z ⋀ z ∈ w)
⋀ (y ∈ w ⋀ w
∈ x)) ↔ y = w))) |
| 11 | 9, 10 | syl 10 |
1
⊢ (∀x x = z → ∃x∀y∀z(∀x(y ∈
z ⋀ z ∈ w)
→ ∃w∀y(∃w((y ∈
z ⋀ z ∈ w)
⋀ (y ∈ w ⋀ w
∈ x)) ↔ y = w))) |