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Theorem axnul 2705
Description: The Null Set Axiom of ZF set theory: there exists a set with no elements. Axiom of Empty Set of [Enderton] p. 18. In some textbooks, this is presented as a separate axiom; here we show it can be derived from Separation ax-sep 2699. This version of the Null Set Axiom tells us that at least one empty set exists, but does not tells us that it is unique - we need the Axiom of Extensionality to do that (see zfnuleu 2703).

This proof, suggested by Jeff Hoffman (3-Feb-2008), does not require the set existence axiom ax-9 964, unlike some empty set existence proofs (such as the remark in [Kunen] p. 11). However, it uses ax-4 972, which also presupposes the existence of at least one set, i.e it does not hold in a "free logic" valid in empty domains. Theorem ax4 971, which shows the redundancy of ax-4 972, depends on ax-9 964 for its proof. See axnul2 2704 for a similar proof directly from ax-rep 2689.

This theorem should not be referenced by any proof. Instead, use ax-nul 2706 below so that the uses of the Null Set Axiom can be more easily identified.

Assertion
Ref Expression
axnul xy ¬ yx
Distinct variable group:   x,y

Proof of Theorem axnul
StepHypRef Expression
1 ax-sep 2699 . 2 xy(yx ↔ (yz ⋀ (yy ⋀ ¬ yy)))
2 pm3.24 657 . . . . . 6 ¬ (yy ⋀ ¬ yy)
32intnan 690 . . . . 5 ¬ (yz ⋀ (yy ⋀ ¬ yy))
4 id 59 . . . . 5 ((yx ↔ (yz ⋀ (yy ⋀ ¬ yy))) → (yx ↔ (yz ⋀ (yy ⋀ ¬ yy))))
53, 4mtbiri 716 . . . 4 ((yx ↔ (yz ⋀ (yy ⋀ ¬ yy))) → ¬ yx)
6519.20i 991 . . 3 (∀y(yx ↔ (yz ⋀ (yy ⋀ ¬ yy))) → ∀y ¬ yx)
7619.22i 1039 . 2 (∃xy(yx ↔ (yz ⋀ (yy ⋀ ¬ yy))) → ∃xy ¬ yx)
81, 7ax-mp 7 1 xy ¬ yx
Colors of variables: wff set class
Syntax hints:  ¬ wn 2   ↔ wb 146   ⋀ wa 223  ∀wal 953   ∈ wcel 957  ∃wex 979
This theorem is referenced by:  snex 2746
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 962  ax-4 972  ax-5o 974  ax-sep 2699
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 980
Copyright terms: Public domain