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Theorem falimd 1496
Description: The truth value implies anything. (Contributed by Mario Carneiro, 9-Feb-2017.)
Assertion
Ref Expression
falimd ((𝜑 ∧ ⊥) → 𝜓)

Proof of Theorem falimd
StepHypRef Expression
1 falim 1495 . 2 (⊥ → 𝜓)
21adantl 482 1 ((𝜑 ∧ ⊥) → 𝜓)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 384  wfal 1485
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 197  df-an 386  df-tru 1483  df-fal 1486
This theorem is referenced by: (None)
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