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Theorem flddivrng 35279
Description: A field is a division ring. (Contributed by Jeff Madsen, 10-Jun-2010.) (Revised by Mario Carneiro, 15-Dec-2013.) (New usage is discouraged.)
Assertion
Ref Expression
flddivrng (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps)

Proof of Theorem flddivrng
StepHypRef Expression
1 df-fld 35272 . . 3 Fld = (DivRingOps ∩ Com2)
2 inss1 4207 . . 3 (DivRingOps ∩ Com2) ⊆ DivRingOps
31, 2eqsstri 4003 . 2 Fld ⊆ DivRingOps
43sseli 3965 1 (𝐾 ∈ Fld → 𝐾 ∈ DivRingOps)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wcel 2114  cin 3937  DivRingOpscdrng 35228  Com2ccm2 35269  Fldcfld 35271
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2116  ax-9 2124  ax-10 2145  ax-11 2161  ax-12 2177  ax-ext 2795
This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-tru 1540  df-ex 1781  df-nf 1785  df-sb 2070  df-clab 2802  df-cleq 2816  df-clel 2895  df-nfc 2965  df-v 3498  df-in 3945  df-ss 3954  df-fld 35272
This theorem is referenced by:  isfld2  35285  isfldidl  35348
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