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Theorem ineqcom 35506
Description: Two ways of saying that two classes are disjoint (when 𝐶 = ∅: ((𝐴𝐵) = ∅ ↔ (𝐵𝐴) = ∅)). (Contributed by Peter Mazsa, 22-Mar-2017.)
Assertion
Ref Expression
ineqcom ((𝐴𝐵) = 𝐶 ↔ (𝐵𝐴) = 𝐶)

Proof of Theorem ineqcom
StepHypRef Expression
1 incom 4180 . 2 (𝐴𝐵) = (𝐵𝐴)
21eqeq1i 2828 1 ((𝐴𝐵) = 𝐶 ↔ (𝐵𝐴) = 𝐶)
Colors of variables: wff setvar class
Syntax hints:  wb 208   = wceq 1537  cin 3937
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-9 2124  ax-ext 2795
This theorem depends on definitions:  df-bi 209  df-an 399  df-tru 1540  df-ex 1781  df-sb 2070  df-clab 2802  df-cleq 2816  df-rab 3149  df-in 3945
This theorem is referenced by:  ineqcomi  35507
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