Proof of Theorem ipasslem4
| Step | Hyp | Ref
| Expression |
| 1 | | recidt 5742 |
. . . . . . 7
⊢ ((N ∈ ℂ ⋀ N ≠ 0) → (N · (1 / N)) = 1) |
| 2 | | nncnt 5932 |
. . . . . . 7
⊢ (N ∈ ℕ → N
∈ ℂ) |
| 3 | | nnne0t 5951 |
. . . . . . 7
⊢ (N ∈ ℕ → N
≠ 0) |
| 4 | 1, 2, 3 | sylanc 473 |
. . . . . 6
⊢ (N ∈ ℕ → (N
· (1 / N)) = 1) |
| 5 | 4 | opreq1d 3981 |
. . . . 5
⊢ (N ∈ ℕ → ((N
· (1 / N)) · (APB)) = (1 · (APB))) |
| 6 | | ip1i.9 |
. . . . . . . 8
⊢ U ∈
CPreHil |
| 7 | 6 | phnvi 8471 |
. . . . . . 7
⊢ U ∈
NrmCVec |
| 8 | | ipasslem1.b |
. . . . . . 7
⊢ B ∈ X |
| 9 | | ip1i.1 |
. . . . . . . 8
⊢ X = (Base ‘U) |
| 10 | | ip1i.7 |
. . . . . . . 8
⊢ P = ( ·i
‘U) |
| 11 | 9, 10 | ipcl 8361 |
. . . . . . 7
⊢ ((U ∈ NrmCVec ⋀ A ∈ X ⋀ B ∈ X) →
(APB) ∈ ℂ) |
| 12 | 7, 8, 11 | mp3an13 909 |
. . . . . 6
⊢ (A ∈ X → (APB) ∈ ℂ) |
| 13 | | mulid2t 5429 |
. . . . . 6
⊢ ((APB) ∈ ℂ → (1 · (APB)) = (APB)) |
| 14 | 12, 13 | syl 10 |
. . . . 5
⊢ (A ∈ X → (1 · (APB)) = (APB)) |
| 15 | 5, 14 | sylan9eq 1530 |
. . . 4
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((N
· (1 / N)) · (APB)) = (APB)) |
| 16 | 4 | opreq1d 3981 |
. . . . . . 7
⊢ (N ∈ ℕ → ((N
· (1 / N))SA) = (1SA)) |
| 17 | | ip1i.4 |
. . . . . . . . 9
⊢ S = ( ·s
‘U) |
| 18 | 9, 17 | nvsid 8244 |
. . . . . . . 8
⊢ ((U ∈ NrmCVec ⋀ A ∈ X) →
(1SA) =
A) |
| 19 | 7, 18 | mpan 697 |
. . . . . . 7
⊢ (A ∈ X → (1SA) = A) |
| 20 | 16, 19 | sylan9eq 1530 |
. . . . . 6
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((N
· (1 / N))SA) = A) |
| 21 | 9, 17 | nvsass 8245 |
. . . . . . . 8
⊢ ((U ∈ NrmCVec ⋀ (N ∈ ℂ ⋀ (1 / N)
∈ ℂ ⋀ A ∈ X)) →
((N · (1 / N))SA) = (NS((1 / N)SA))) |
| 22 | 7, 21 | mpan 697 |
. . . . . . 7
⊢ ((N ∈ ℂ ⋀ (1 /
N) ∈
ℂ ⋀
A ∈
X) → ((N · (1 / N))SA) = (NS((1 / N)SA))) |
| 23 | 2 | adantr 391 |
. . . . . . 7
⊢ ((N ∈ ℕ ⋀ A ∈ X) → N
∈ ℂ) |
| 24 | | nnrecret 5954 |
. . . . . . . . 9
⊢ (N ∈ ℕ → (1 / N) ∈ ℝ) |
| 25 | 24 | recnd 5327 |
. . . . . . . 8
⊢ (N ∈ ℕ → (1 / N) ∈ ℂ) |
| 26 | 25 | adantr 391 |
. . . . . . 7
⊢ ((N ∈ ℕ ⋀ A ∈ X) → (1 / N) ∈ ℂ) |
| 27 | | pm3.27 323 |
. . . . . . 7
⊢ ((N ∈ ℕ ⋀ A ∈ X) → A
∈ X) |
| 28 | 22, 23, 26, 27 | syl3anc 860 |
. . . . . 6
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((N
· (1 / N))SA) = (NS((1 / N)SA))) |
| 29 | 20, 28 | eqtr3d 1512 |
. . . . 5
⊢ ((N ∈ ℕ ⋀ A ∈ X) → A =
(NS((1
/ N)SA))) |
| 30 | 29 | opreq1d 3981 |
. . . 4
⊢ ((N ∈ ℕ ⋀ A ∈ X) → (APB) = ((NS((1 / N)SA))PB)) |
| 31 | 15, 30 | eqtr2d 1511 |
. . 3
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((NS((1 / N)SA))PB) = ((N
· (1 / N)) · (APB))) |
| 32 | | ip1i.2 |
. . . . 5
⊢ G = ( +v ‘U) |
| 33 | 9, 32, 17, 10, 6, 8 | ipasslem1 8486 |
. . . 4
⊢ ((N ∈ ℕ0 ⋀
((1 / N)SA) ∈ X) →
((NS((1
/ N)SA))PB) = (N · (((1 / N)SA)PB))) |
| 34 | | nnnn0t 6108 |
. . . . 5
⊢ (N ∈ ℕ → N
∈ ℕ0) |
| 35 | 34 | adantr 391 |
. . . 4
⊢ ((N ∈ ℕ ⋀ A ∈ X) → N
∈ ℕ0) |
| 36 | 9, 17 | nvscl 8243 |
. . . . . 6
⊢ ((U ∈ NrmCVec ⋀ (1 / N)
∈ ℂ ⋀ A ∈ X) → ((1
/ N)SA) ∈ X) |
| 37 | 7, 36 | mp3an1 905 |
. . . . 5
⊢ (((1 / N) ∈ ℂ ⋀ A ∈ X) → ((1 / N)SA) ∈ X) |
| 38 | 37, 25 | sylan 450 |
. . . 4
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((1 / N)SA) ∈ X) |
| 39 | 33, 35, 38 | sylanc 473 |
. . 3
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((NS((1 / N)SA))PB) = (N ·
(((1 / N)SA)PB))) |
| 40 | | axmulass 5290 |
. . . 4
⊢ ((N ∈ ℂ ⋀ (1 /
N) ∈
ℂ ⋀
(APB) ∈ ℂ) →
((N · (1 / N)) · (APB)) = (N
· ((1 / N) · (APB)))) |
| 41 | 12 | adantl 390 |
. . . 4
⊢ ((N ∈ ℕ ⋀ A ∈ X) → (APB) ∈ ℂ) |
| 42 | 40, 23, 26, 41 | syl3anc 860 |
. . 3
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((N
· (1 / N)) · (APB)) = (N
· ((1 / N) · (APB)))) |
| 43 | 31, 39, 42 | 3eqtr3d 1518 |
. 2
⊢ ((N ∈ ℕ ⋀ A ∈ X) → (N
· (((1 / N)SA)PB)) = (N · ((1 / N) · (APB)))) |
| 44 | | mulcantOLD 5703 |
. . 3
⊢ (((N ∈ ℂ ⋀ (((1 /
N)SA)PB) ∈ ℂ ⋀ ((1 / N)
· (APB)) ∈ ℂ) ⋀ N ≠ 0)
→ ((N · (((1 / N)SA)PB)) = (N
· ((1 / N) · (APB))) ↔ (((1 / N)SA)PB) = ((1 / N)
· (APB)))) |
| 45 | 9, 10 | ipcl 8361 |
. . . . . 6
⊢ ((U ∈ NrmCVec ⋀ ((1 / N)SA) ∈ X ⋀ B ∈ X) → (((1 / N)SA)PB) ∈ ℂ) |
| 46 | 7, 8, 45 | mp3an13 909 |
. . . . 5
⊢ (((1 / N)SA) ∈ X → (((1 / N)SA)PB) ∈ ℂ) |
| 47 | 38, 46 | syl 10 |
. . . 4
⊢ ((N ∈ ℕ ⋀ A ∈ X) → (((1 / N)SA)PB) ∈ ℂ) |
| 48 | | axmulcl 5285 |
. . . . 5
⊢ (((1 / N) ∈ ℂ ⋀ (APB) ∈ ℂ) → ((1 / N) · (APB)) ∈ ℂ) |
| 49 | 48, 25, 12 | syl2an 456 |
. . . 4
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((1 / N) · (APB)) ∈ ℂ) |
| 50 | 23, 47, 49 | 3jca 821 |
. . 3
⊢ ((N ∈ ℕ ⋀ A ∈ X) → (N
∈ ℂ ⋀ (((1 / N)SA)PB) ∈ ℂ ⋀ ((1 /
N) · (APB)) ∈ ℂ)) |
| 51 | 3 | adantr 391 |
. . 3
⊢ ((N ∈ ℕ ⋀ A ∈ X) → N ≠
0) |
| 52 | 44, 50, 51 | sylanc 473 |
. 2
⊢ ((N ∈ ℕ ⋀ A ∈ X) → ((N
· (((1 / N)SA)PB)) = (N · ((1 / N) · (APB))) ↔ (((1 / N)SA)PB) = ((1 / N)
· (APB)))) |
| 53 | 43, 52 | mpbid 195 |
1
⊢ ((N ∈ ℕ ⋀ A ∈ X) → (((1 / N)SA)PB) = ((1 / N)
· (APB))) |