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Theorem ndmaovcom 40615
Description: Any operation is commutative outside its domain, analogous to ndmovcom 6781. (Contributed by Alexander van der Vekens, 26-May-2017.)
Hypothesis
Ref Expression
ndmaov.1 dom 𝐹 = (𝑆 × 𝑆)
Assertion
Ref Expression
ndmaovcom (¬ (𝐴𝑆𝐵𝑆) → ((𝐴𝐹𝐵)) = ((𝐵𝐹𝐴)) )

Proof of Theorem ndmaovcom
StepHypRef Expression
1 opelxp 5111 . . . 4 (⟨𝐴, 𝐵⟩ ∈ (𝑆 × 𝑆) ↔ (𝐴𝑆𝐵𝑆))
2 ndmaov.1 . . . . . 6 dom 𝐹 = (𝑆 × 𝑆)
32eqcomi 2630 . . . . 5 (𝑆 × 𝑆) = dom 𝐹
43eleq2i 2690 . . . 4 (⟨𝐴, 𝐵⟩ ∈ (𝑆 × 𝑆) ↔ ⟨𝐴, 𝐵⟩ ∈ dom 𝐹)
51, 4bitr3i 266 . . 3 ((𝐴𝑆𝐵𝑆) ↔ ⟨𝐴, 𝐵⟩ ∈ dom 𝐹)
6 ndmaov 40593 . . 3 (¬ ⟨𝐴, 𝐵⟩ ∈ dom 𝐹 → ((𝐴𝐹𝐵)) = V)
75, 6sylnbi 320 . 2 (¬ (𝐴𝑆𝐵𝑆) → ((𝐴𝐹𝐵)) = V)
8 ancom 466 . . . 4 ((𝐴𝑆𝐵𝑆) ↔ (𝐵𝑆𝐴𝑆))
9 opelxp 5111 . . . 4 (⟨𝐵, 𝐴⟩ ∈ (𝑆 × 𝑆) ↔ (𝐵𝑆𝐴𝑆))
103eleq2i 2690 . . . 4 (⟨𝐵, 𝐴⟩ ∈ (𝑆 × 𝑆) ↔ ⟨𝐵, 𝐴⟩ ∈ dom 𝐹)
118, 9, 103bitr2i 288 . . 3 ((𝐴𝑆𝐵𝑆) ↔ ⟨𝐵, 𝐴⟩ ∈ dom 𝐹)
12 ndmaov 40593 . . 3 (¬ ⟨𝐵, 𝐴⟩ ∈ dom 𝐹 → ((𝐵𝐹𝐴)) = V)
1311, 12sylnbi 320 . 2 (¬ (𝐴𝑆𝐵𝑆) → ((𝐵𝐹𝐴)) = V)
147, 13eqtr4d 2658 1 (¬ (𝐴𝑆𝐵𝑆) → ((𝐴𝐹𝐵)) = ((𝐵𝐹𝐴)) )
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wa 384   = wceq 1480  wcel 1987  Vcvv 3189  cop 4159   × cxp 5077  dom cdm 5079   ((caov 40525
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1719  ax-4 1734  ax-5 1836  ax-6 1885  ax-7 1932  ax-9 1996  ax-10 2016  ax-11 2031  ax-12 2044  ax-13 2245  ax-ext 2601  ax-sep 4746  ax-nul 4754  ax-pr 4872
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3an 1038  df-tru 1483  df-ex 1702  df-nf 1707  df-sb 1878  df-clab 2608  df-cleq 2614  df-clel 2617  df-nfc 2750  df-ral 2912  df-rex 2913  df-rab 2916  df-v 3191  df-dif 3562  df-un 3564  df-in 3566  df-ss 3573  df-nul 3897  df-if 4064  df-sn 4154  df-pr 4156  df-op 4160  df-opab 4679  df-xp 5085  df-fv 5860  df-dfat 40526  df-afv 40527  df-aov 40528
This theorem is referenced by: (None)
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