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Theorem ordsucun 6975
Description: The successor of the maximum (i.e. union) of two ordinals is the maximum of their successors. (Contributed by NM, 28-Nov-2003.)
Assertion
Ref Expression
ordsucun ((Ord 𝐴 ∧ Ord 𝐵) → suc (𝐴𝐵) = (suc 𝐴 ∪ suc 𝐵))

Proof of Theorem ordsucun
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 ordun 5790 . . . 4 ((Ord 𝐴 ∧ Ord 𝐵) → Ord (𝐴𝐵))
2 ordsuc 6964 . . . . 5 (Ord (𝐴𝐵) ↔ Ord suc (𝐴𝐵))
3 ordelon 5708 . . . . . 6 ((Ord suc (𝐴𝐵) ∧ 𝑥 ∈ suc (𝐴𝐵)) → 𝑥 ∈ On)
43ex 450 . . . . 5 (Ord suc (𝐴𝐵) → (𝑥 ∈ suc (𝐴𝐵) → 𝑥 ∈ On))
52, 4sylbi 207 . . . 4 (Ord (𝐴𝐵) → (𝑥 ∈ suc (𝐴𝐵) → 𝑥 ∈ On))
61, 5syl 17 . . 3 ((Ord 𝐴 ∧ Ord 𝐵) → (𝑥 ∈ suc (𝐴𝐵) → 𝑥 ∈ On))
7 ordsuc 6964 . . . 4 (Ord 𝐴 ↔ Ord suc 𝐴)
8 ordsuc 6964 . . . 4 (Ord 𝐵 ↔ Ord suc 𝐵)
9 ordun 5790 . . . . 5 ((Ord suc 𝐴 ∧ Ord suc 𝐵) → Ord (suc 𝐴 ∪ suc 𝐵))
10 ordelon 5708 . . . . . 6 ((Ord (suc 𝐴 ∪ suc 𝐵) ∧ 𝑥 ∈ (suc 𝐴 ∪ suc 𝐵)) → 𝑥 ∈ On)
1110ex 450 . . . . 5 (Ord (suc 𝐴 ∪ suc 𝐵) → (𝑥 ∈ (suc 𝐴 ∪ suc 𝐵) → 𝑥 ∈ On))
129, 11syl 17 . . . 4 ((Ord suc 𝐴 ∧ Ord suc 𝐵) → (𝑥 ∈ (suc 𝐴 ∪ suc 𝐵) → 𝑥 ∈ On))
137, 8, 12syl2anb 496 . . 3 ((Ord 𝐴 ∧ Ord 𝐵) → (𝑥 ∈ (suc 𝐴 ∪ suc 𝐵) → 𝑥 ∈ On))
14 ordssun 5788 . . . . . . 7 ((Ord 𝐴 ∧ Ord 𝐵) → (𝑥 ⊆ (𝐴𝐵) ↔ (𝑥𝐴𝑥𝐵)))
1514adantl 482 . . . . . 6 ((𝑥 ∈ On ∧ (Ord 𝐴 ∧ Ord 𝐵)) → (𝑥 ⊆ (𝐴𝐵) ↔ (𝑥𝐴𝑥𝐵)))
16 ordsssuc 5773 . . . . . . 7 ((𝑥 ∈ On ∧ Ord (𝐴𝐵)) → (𝑥 ⊆ (𝐴𝐵) ↔ 𝑥 ∈ suc (𝐴𝐵)))
171, 16sylan2 491 . . . . . 6 ((𝑥 ∈ On ∧ (Ord 𝐴 ∧ Ord 𝐵)) → (𝑥 ⊆ (𝐴𝐵) ↔ 𝑥 ∈ suc (𝐴𝐵)))
18 ordsssuc 5773 . . . . . . . 8 ((𝑥 ∈ On ∧ Ord 𝐴) → (𝑥𝐴𝑥 ∈ suc 𝐴))
1918adantrr 752 . . . . . . 7 ((𝑥 ∈ On ∧ (Ord 𝐴 ∧ Ord 𝐵)) → (𝑥𝐴𝑥 ∈ suc 𝐴))
20 ordsssuc 5773 . . . . . . . 8 ((𝑥 ∈ On ∧ Ord 𝐵) → (𝑥𝐵𝑥 ∈ suc 𝐵))
2120adantrl 751 . . . . . . 7 ((𝑥 ∈ On ∧ (Ord 𝐴 ∧ Ord 𝐵)) → (𝑥𝐵𝑥 ∈ suc 𝐵))
2219, 21orbi12d 745 . . . . . 6 ((𝑥 ∈ On ∧ (Ord 𝐴 ∧ Ord 𝐵)) → ((𝑥𝐴𝑥𝐵) ↔ (𝑥 ∈ suc 𝐴𝑥 ∈ suc 𝐵)))
2315, 17, 223bitr3d 298 . . . . 5 ((𝑥 ∈ On ∧ (Ord 𝐴 ∧ Ord 𝐵)) → (𝑥 ∈ suc (𝐴𝐵) ↔ (𝑥 ∈ suc 𝐴𝑥 ∈ suc 𝐵)))
24 elun 3733 . . . . 5 (𝑥 ∈ (suc 𝐴 ∪ suc 𝐵) ↔ (𝑥 ∈ suc 𝐴𝑥 ∈ suc 𝐵))
2523, 24syl6bbr 278 . . . 4 ((𝑥 ∈ On ∧ (Ord 𝐴 ∧ Ord 𝐵)) → (𝑥 ∈ suc (𝐴𝐵) ↔ 𝑥 ∈ (suc 𝐴 ∪ suc 𝐵)))
2625expcom 451 . . 3 ((Ord 𝐴 ∧ Ord 𝐵) → (𝑥 ∈ On → (𝑥 ∈ suc (𝐴𝐵) ↔ 𝑥 ∈ (suc 𝐴 ∪ suc 𝐵))))
276, 13, 26pm5.21ndd 369 . 2 ((Ord 𝐴 ∧ Ord 𝐵) → (𝑥 ∈ suc (𝐴𝐵) ↔ 𝑥 ∈ (suc 𝐴 ∪ suc 𝐵)))
2827eqrdv 2619 1 ((Ord 𝐴 ∧ Ord 𝐵) → suc (𝐴𝐵) = (suc 𝐴 ∪ suc 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 196  wo 383  wa 384   = wceq 1480  wcel 1987  cun 3554  wss 3556  Ord word 5683  Oncon0 5684  suc csuc 5686
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1719  ax-4 1734  ax-5 1836  ax-6 1885  ax-7 1932  ax-8 1989  ax-9 1996  ax-10 2016  ax-11 2031  ax-12 2044  ax-13 2245  ax-ext 2601  ax-sep 4743  ax-nul 4751  ax-pr 4869  ax-un 6905
This theorem depends on definitions:  df-bi 197  df-or 385  df-an 386  df-3or 1037  df-3an 1038  df-tru 1483  df-ex 1702  df-nf 1707  df-sb 1878  df-eu 2473  df-mo 2474  df-clab 2608  df-cleq 2614  df-clel 2617  df-nfc 2750  df-ne 2791  df-ral 2912  df-rex 2913  df-rab 2916  df-v 3188  df-sbc 3419  df-dif 3559  df-un 3561  df-in 3563  df-ss 3570  df-pss 3572  df-nul 3894  df-if 4061  df-sn 4151  df-pr 4153  df-tp 4155  df-op 4157  df-uni 4405  df-br 4616  df-opab 4676  df-tr 4715  df-eprel 4987  df-po 4997  df-so 4998  df-fr 5035  df-we 5037  df-ord 5687  df-on 5688  df-suc 5690
This theorem is referenced by:  rankprb  8661
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