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Theorem sbal 1345
Description: Move universal quantifier in and out of substitution.
Assertion
Ref Expression
sbal ([z / y]∀xφ ↔ ∀x[z / y]φ)
Distinct variable groups:   x,y   x,z

Proof of Theorem sbal
StepHypRef Expression
1 a16gb 1275 . . . . 5 (∀x x = z → (φ ↔ ∀xφ))
21sbimi 1171 . . . 4 ([z / y]∀x x = z → [z / y](φ ↔ ∀xφ))
3 sbequ5 1188 . . . 4 ([z / y]∀x x = z ↔ ∀x x = z)
4 sbbi 1237 . . . 4 ([z / y](φ ↔ ∀xφ) ↔ ([z / y]φ ↔ [z / y]∀xφ))
52, 3, 43imtr3 218 . . 3 (∀x x = z → ([z / y]φ ↔ [z / y]∀xφ))
6 a16gb 1275 . . 3 (∀x x = z → ([z / y]φ ↔ ∀x[z / y]φ))
75, 6bitr3d 529 . 2 (∀x x = z → ([z / y]∀xφ ↔ ∀x[z / y]φ))
8 sbal1 1344 . 2 (¬ ∀x x = z → ([z / y]∀xφ ↔ ∀x[z / y]φ))
97, 8pm2.61i 126 1 ([z / y]∀xφ ↔ ∀x[z / y]φ)
Colors of variables: wff set class
Syntax hints:   ↔ wb 146  ∀wal 952  [wsbc 1168
This theorem is referenced by:  sbex 1346  sbalv 1347  sbabel 1581  sbcalg 1970
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 960  ax-gen 961  ax-8 962  ax-9 963  ax-10 964  ax-12 966  ax-4 971  ax-5o 973  ax-6o 976  ax-9o 1121  ax-10o 1138  ax-16 1208  ax-11o 1216
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 979  df-sb 1170
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