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Theorem sbc2or 1954
Description: The disjunction of two equivalences for class substitution does not require a class existence hypothesis.
Assertion
Ref Expression
sbc2or (([A / x]φ ↔ ∃x(x = Aφ)) ⋁ ([A / x]φ ↔ ∀x(x = Aφ)))
Distinct variable group:   x,A

Proof of Theorem sbc2or
StepHypRef Expression
1 sbc5g 1950 . . 3 (AV → ([A / x]φ ↔ ∃x(x = Aφ)))
21orcd 272 . 2 (AV → (([A / x]φ ↔ ∃x(x = Aφ)) ⋁ ([A / x]φ ↔ ∀x(x = Aφ))))
3 pm5.15 665 . . 3 (([A / x]φ ↔ ∃x(x = Aφ)) ⋁ ([A / x]φ ↔ ¬ ∃x(x = Aφ)))
4 pm5.1 675 . . . . . 6 ((¬ ∃x(x = Aφ) ⋀ ∀x(x = Aφ)) → (¬ ∃x(x = Aφ) ↔ ∀x(x = Aφ)))
5 visset 1809 . . . . . . . . . 10 xV
6 eleq1 1531 . . . . . . . . . 10 (x = A → (xVAV))
75, 6mpbii 193 . . . . . . . . 9 (x = AAV)
87adantr 389 . . . . . . . 8 ((x = Aφ) → AV)
98con3i 98 . . . . . . 7 AV → ¬ (x = Aφ))
109nexdv 1324 . . . . . 6 AV → ¬ ∃x(x = Aφ))
117con3i 98 . . . . . . . 8 AV → ¬ x = A)
1211pm2.21d 78 . . . . . . 7 AV → (x = Aφ))
131219.21aiv 1284 . . . . . 6 AV → ∀x(x = Aφ))
144, 10, 13sylanc 471 . . . . 5 AV → (¬ ∃x(x = Aφ) ↔ ∀x(x = Aφ)))
1514bibi2d 617 . . . 4 AV → (([A / x]φ ↔ ¬ ∃x(x = Aφ)) ↔ ([A / x]φ ↔ ∀x(x = Aφ))))
1615orbi2d 613 . . 3 AV → ((([A / x]φ ↔ ∃x(x = Aφ)) ⋁ ([A / x]φ ↔ ¬ ∃x(x = Aφ))) ↔ (([A / x]φ ↔ ∃x(x = Aφ)) ⋁ ([A / x]φ ↔ ∀x(x = Aφ)))))
173, 16mpbii 193 . 2 AV → (([A / x]φ ↔ ∃x(x = Aφ)) ⋁ ([A / x]φ ↔ ∀x(x = Aφ))))
182, 17pm2.61i 126 1 (([A / x]φ ↔ ∃x(x = Aφ)) ⋁ ([A / x]φ ↔ ∀x(x = Aφ)))
Colors of variables: wff set class
Syntax hints:  ¬ wn 2   → wi 3   ↔ wb 146   ⋁ wo 222   ⋀ wa 223  ∀wal 952   = wceq 954   ∈ wcel 956  ∃wex 978  [wsbc 1168  Vcvv 1807
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 960  ax-gen 961  ax-8 962  ax-10 964  ax-12 966  ax-17 969  ax-4 971  ax-5o 973  ax-6o 976  ax-9o 1121  ax-10o 1138  ax-16 1208  ax-11o 1216  ax-ext 1457
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 979  df-sb 1170  df-clab 1462  df-cleq 1467  df-clel 1470  df-v 1808  df-sbc 1938
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