Theorem sbcth 3789

Description: A substitution into a theorem remains true (when 𝐴 is a set). (Contributed by NM, 5-Nov-2005.)

Hypothesis

Ref	Expression
sbcth.1	⊢ 𝜑

Assertion

Ref	Expression
sbcth	⊢ (𝐴 ∈ 𝑉 → [𝐴 / 𝑥]𝜑)

Proof of Theorem sbcth

Step	Hyp	Ref	Expression
1		sbcth.1	. . 3 ⊢ 𝜑
2	1	ax-gen 1796	. 2 ⊢ ∀𝑥𝜑
3		spsbc 3787	. 2 ⊢ (𝐴 ∈ 𝑉 → (∀𝑥𝜑 → [𝐴 / 𝑥]𝜑))
4	2, 3	mpi 20	1 ⊢ (𝐴 ∈ 𝑉 → [𝐴 / 𝑥]𝜑)

Syntax hints:   → wi 4  ∀wal 1535   ∈ wcel 2114  [wsbc 3774

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2116  ax-9 2124  ax-ext 2795

This theorem depends on definitions:  df-bi 209  df-an 399  df-ex 1781  df-sb 2070  df-clab 2802  df-cleq 2816  df-clel 2895  df-sbc 3775

This theorem is referenced by:  iota4an  6339  tfinds2  7580  wunnat  17228  catcfuccl  17371  dprdval  19127  opsbc2ie  30241  bj-sbceqgALT  34221  f1omptsnlem  34619  mptsnunlem  34621  topdifinffinlem  34630  relowlpssretop  34647  cdlemk35s  38075  cdlemk39s  38077  cdlemk42  38079  frege92  40308