NFE Home New Foundations Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  NFE Home  >  Th. List  >  disj2 GIF version

Theorem disj2 3598
Description: Two ways of saying that two classes are disjoint. (Contributed by NM, 17-May-1998.)
Assertion
Ref Expression
disj2 ((AB) = A (V B))

Proof of Theorem disj2
StepHypRef Expression
1 ssv 3291 . 2 A V
2 reldisj 3594 . 2 (A V → ((AB) = A (V B)))
31, 2ax-mp 5 1 ((AB) = A (V B))
Colors of variables: wff setvar class
Syntax hints:  wb 176   = wceq 1642  Vcvv 2859   cdif 3206  cin 3208   wss 3257  c0 3550
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334
This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2478  df-ne 2518  df-ral 2619  df-v 2861  df-nin 3211  df-compl 3212  df-in 3213  df-dif 3215  df-ss 3259  df-nul 3551
This theorem is referenced by:  ssindif0  3604
  Copyright terms: Public domain W3C validator