Theorem biadanii 602

Description: Inference associated with biadani 601. Add a conjunction to an equivalence. (Contributed by Jeff Madsen, 20-Jun-2011.) (Proof shortened by BJ, 4-Mar-2023.)

Hypotheses

Ref	Expression
biadani.1	⊢ (𝜑 → 𝜓)
biadanii.2	⊢ (𝜓 → (𝜑 ↔ 𝜒))

Assertion

Ref	Expression
biadanii	⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))

Proof of Theorem biadanii

Step	Hyp	Ref	Expression
1		biadanii.2	. 2 ⊢ (𝜓 → (𝜑 ↔ 𝜒))
2		biadani.1	. . 3 ⊢ (𝜑 → 𝜓)
3	2	biadani 601	. 2 ⊢ ((𝜓 → (𝜑 ↔ 𝜒)) ↔ (𝜑 ↔ (𝜓 ∧ 𝜒)))
4	1, 3	mpbi 144	1 ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))

Syntax hints:   → wi 4   ∧ wa 103   ↔ wb 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107

This theorem depends on definitions:  df-bi 116

This theorem is referenced by:  iscn2  12379