Theorem falimd 1329

Description: F. implies anything. (Contributed by Mario Carneiro, 9-Feb-2017.)

Assertion

Ref	Expression
falimd	|- ((ph /\ F. ) -> ps)

Proof of Theorem falimd

Step	Hyp	Ref	Expression
1		falim 1328	. 2 |- ( F. -> ps)
2	1	adantl 452	1 |- ((ph /\ F. ) -> ps)

Syntax hints:   -> wi 4   /\ wa 358   F. wfal 1317

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 177  df-an 360  df-tru 1319  df-fal 1320

This theorem is referenced by: (None)