Detailed syntax breakdown of Axiom ax-pow
| Step | Hyp | Ref
| Expression |
| 1 | | vw |
. . . . . . . 8
set w |
| 2 | 1 | cv 953 |
. . . . . . 7
class w |
| 3 | | vz |
. . . . . . . 8
set z |
| 4 | 3 | cv 953 |
. . . . . . 7
class z |
| 5 | 2, 4 | wcel 956 |
. . . . . 6
wff w ∈
z |
| 6 | | vx |
. . . . . . . 8
set x |
| 7 | 6 | cv 953 |
. . . . . . 7
class x |
| 8 | 2, 7 | wcel 956 |
. . . . . 6
wff w ∈
x |
| 9 | 5, 8 | wi 3 |
. . . . 5
wff (w ∈
z → w ∈ x) |
| 10 | 9, 1 | wal 952 |
. . . 4
wff ∀w(w ∈
z → w ∈ x) |
| 11 | | vy |
. . . . . 6
set y |
| 12 | 11 | cv 953 |
. . . . 5
class y |
| 13 | 4, 12 | wcel 956 |
. . . 4
wff z ∈
y |
| 14 | 10, 13 | wi 3 |
. . 3
wff (∀w(w ∈
z → w ∈ x)
→ z ∈ y) |
| 15 | 14, 3 | wal 952 |
. 2
wff ∀z(∀w(w ∈
z → w ∈ x)
→ z ∈ y) |
| 16 | 15, 11 | wex 978 |
1
wff ∃y∀z(∀w(w ∈
z → w ∈ x)
→ z ∈ y) |