Users' Mathboxes Mathbox for David A. Wheeler < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  ILE Home  >  Th. List  >   Mathboxes  >  alseud Unicode version

Theorem alseud 17141
Description: Introduction rule: "all some one" holds if the "for all" part holds and the antecedent has exactly one witness. This is the converse of alseu1d 17143 and alseu2d 17144 taken together. (Contributed by David A. Wheeler, 22-Jul-2026.)
Hypotheses
Ref Expression
alseud.1  |-  ( ph  ->  A. x ( ps 
->  ch ) )
alseud.2  |-  ( ph  ->  E! x ps )
Assertion
Ref Expression
alseud  |-  ( ph  ->  A.E! x ( ps  ->  ch )
)

Proof of Theorem alseud
StepHypRef Expression
1 alseud.1 . 2  |-  ( ph  ->  A. x ( ps 
->  ch ) )
2 alseud.2 . 2  |-  ( ph  ->  E! x ps )
3 df-alseu 17136 . 2  |-  ( A.E! x ( ps  ->  ch )  <->  ( A. x
( ps  ->  ch )  /\  E! x ps ) )
41, 2, 3sylanbrc 421 1  |-  ( ph  ->  A.E! x ( ps  ->  ch )
)
Colors of variables: wff set class
Syntax hints:    -> wi 4   A.wal 1400   E!weu 2086   A.E!walseu 17134
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108
This theorem depends on definitions:  df-bi 117  df-alseu 17136
This theorem is referenced by: (None)
  Copyright terms: Public domain W3C validator