| Mathbox for David A. Wheeler |
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| Mirrors > Home > ILE Home > Th. List > Mathboxes > alseud | Unicode version | ||
| Description: Introduction rule: "all some one" holds if the "for all" part holds and the antecedent has exactly one witness. This is the converse of alseu1d 17388 and alseu2d 17389 taken together. (Contributed by David A. Wheeler, 22-Jul-2026.) |
| Ref | Expression |
|---|---|
| alseud.1 |
|
| alseud.2 |
|
| Ref | Expression |
|---|---|
| alseud |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | alseud.1 |
. 2
| |
| 2 | alseud.2 |
. 2
| |
| 3 | df-alseu 17381 |
. 2
| |
| 4 | 1, 2, 3 | sylanbrc 421 |
1
|
| Colors of variables: wff set class |
| This proof depends on syntax axioms:
|
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 |
| This proof depends on definitions: df-bi 117 df-alseu 17381 |
| This theorem is used by: (None) |
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