Theorem simplld 532

Description: Deduction form of simpll 531, eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019.)

Hypothesis

Ref	Expression
simplld.1	⊢ (𝜑 → ((𝜓 ∧ 𝜒) ∧ 𝜃))

Assertion

Ref	Expression
simplld	⊢ (𝜑 → 𝜓)

Proof of Theorem simplld

Step	Hyp	Ref	Expression
1		simplld.1	. . 3 ⊢ (𝜑 → ((𝜓 ∧ 𝜒) ∧ 𝜃))
2	1	simpld 112	. 2 ⊢ (𝜑 → (𝜓 ∧ 𝜒))
3	2	simpld 112	1 ⊢ (𝜑 → 𝜓)

This proof depends on syntax axioms:   → wi 4   ∧ wa 104

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106

This theorem is used by:  subupgr  16514