Theorem baib 871

Description: Move conjunction outside of biconditional. (Contributed by NM, 13-May-1999.)

Hypothesis

Ref	Expression
baib.1	|- (ph <-> (ps /\ ch))

Assertion

Ref	Expression
baib	|- (ps -> (ph <-> ch))

Proof of Theorem baib

Step	Hyp	Ref	Expression
1		ibar 490	. 2 |- (ps -> (ch <-> (ps /\ ch)))
2		baib.1	. 2 |- (ph <-> (ps /\ ch))
3	1, 2	syl6rbbr 255	1 |- (ps -> (ph <-> ch))

Syntax hints:   -> wi 4   <-> wb 176   /\ wa 358

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 177  df-an 360

This theorem is referenced by:  baibr  872  rbaib  873  ceqsrexbv  2974  elrab3  2996  dfpss3  3356  rabsn  3791  elrint2  3969  fnres  5200  fvmpti  5700