Theorem necom 2598

Description: Commutation of inequality. (Contributed by NM, 14-May-1999.)

Assertion

Ref	Expression
necom	|- (A =/= B <-> B =/= A)

Proof of Theorem necom

Step	Hyp	Ref	Expression
1		eqcom 2355	. 2 |- (A = B <-> B = A)
2	1	necon3bii 2549	1 |- (A =/= B <-> B =/= A)

Syntax hints:   <-> wb 176   =/= wne 2517

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-ext 2334

This theorem depends on definitions:  df-bi 177  df-cleq 2346  df-ne 2519

This theorem is referenced by:  necomi  2599  necomd  2600  0pss  3589  difprsn1  3848  difprsn2  3849  diftpsn3  3850  fvpr1  5450  fvpr2  5451