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Theorem fneq1d 5020
 Description: Equality deduction for function predicate with domain. (Contributed by Paul Chapman, 22-Jun-2011.)
Hypothesis
Ref Expression
fneq1d.1
Assertion
Ref Expression
fneq1d

Proof of Theorem fneq1d
StepHypRef Expression
1 fneq1d.1 . 2
2 fneq1 5018 . 2
31, 2syl 14 1
 Colors of variables: wff set class Syntax hints:   wi 4   wb 103   wceq 1285   wfn 4927 This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-io 663  ax-5 1377  ax-7 1378  ax-gen 1379  ax-ie1 1423  ax-ie2 1424  ax-8 1436  ax-10 1437  ax-11 1438  ax-i12 1439  ax-bndl 1440  ax-4 1441  ax-17 1460  ax-i9 1464  ax-ial 1468  ax-i5r 1469  ax-ext 2064 This theorem depends on definitions:  df-bi 115  df-3an 922  df-tru 1288  df-nf 1391  df-sb 1687  df-clab 2069  df-cleq 2075  df-clel 2078  df-nfc 2209  df-v 2604  df-un 2978  df-in 2980  df-ss 2987  df-sn 3412  df-pr 3413  df-op 3415  df-br 3794  df-opab 3848  df-rel 4378  df-cnv 4379  df-co 4380  df-dm 4381  df-fun 4934  df-fn 4935 This theorem is referenced by:  fneq12d  5022  f1o00  5192  f1ompt  5352  fmpt2d  5359  f1ocnvd  5733  offval2  5757  ofrfval2  5758  caofinvl  5764  f1od2  5887
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